Answer:
The limiting reactant is KOH.
Explanation:
To find the limiting reactant we need to calculate the number of moles of each one:
<u>Where</u>:
η: is the number of moles
m: is the mass
M: is the molar mass
Now, we can find the limiting reactant using the stoichiometric relation between the reactants in the reaction:
We have that between MnO₂ and KOH, the limiting reactant is KOH.
Similarly, we have that between O₂ and Cl₂, the limiting reactant is Cl₂.
Now, the limiting reactant between KOH and Cl₂ is:
Therefore, the limiting reactant is KOH.
I hope it helps you!
<span>Carbon Monoxide.
First, determine the relative number of moles of each element by looking up the atomic weights of carbon and oxygen
Atomic weight carbon = 12.0107
Atomic weight oxygen = 15.999
Moles of Carbon = 24.50 g / 12.0107 g/mol = 2.039847802 mol
Moles of Oxygen = 32.59 g / 15.999 g/mol = 2.037002313 mol
Given that the number of moles of both carbon and oxygen are nearly identical, it wouldn't be unreasonable to think that the empirical formula for the compound is CO which also happens to be the formula for Carbon Monoxide.</span>
Answer:
Mole fraction = 0,0166
Explanation:
Mole fraction is defined as mole of a compound per total moles of the mixture. In the solution, the solute is fructose and the solvent is water. That means you need to find moles of fructose and moles of water.
The molecular mass of fructose is 180,16g/mol and mass of water is 18,02 g/mol. Using these values:
91,7g fructose × (1mol / 180,16g) = <em>0,509 moles of fructose</em>
545g water × (1mol / 18,02g) = <em>30,24 moles of water</em>
Thus, mole fraction of fructose is:
<em>Mole fraction = 0,0166</em>
I hope it helps!
1.always listen to teacher
2 no eating in class
3 always have attentive listening
4 always have proper safety material
5 wear eyeglasses when needed
6 let others be able to listen
sorry I could only think of 6
Answer is: the mass of a block of magnesium is 177.75 grams.
m(Fe) = 826 g.
d(Fe) = 7.9 g/cm³.
1) Calculate volume of iron and magnesium:
d(Fe) = m(Fe) ÷ V(Fe).
V(Fe) = m(Fe) ÷ d(Fe).
V(Fe) = 826 g ÷ 7.9 g/cm³.
V(Fe) = V(Mg) = 104.56 cm³.
2) Calculate mass of magnesium:
m(Mg) = V(Mg) · d(Mg).
m(Mg) = 104.56 g/cm³ · 1.7 g/cm³.
m(Mg) = 177.75 g.
