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wolverine [178]
1 year ago
8

How do you this question? Please help.

Mathematics
1 answer:
dangina [55]1 year ago
5 0
N - Nicholes money
M - Marys money

(1) N + M = 4800 ⇒ N = 4800 - M
(2) N - 800 = M - 2/5M ⇒ N - 800 = 3/5M

subtitute (1) to (2)

4800 - M - 800 = 3/5M
4000 - M = 3/5M
-M - 3/5M = -4000
-8/5M = -4000  |multiply both sides by (-5/8)
M = 2500

subtitute the value of M to (1)

N = 4800 - 2500
N = 2300

Answer: Mary had at first $2500. (Nichole: $2300).
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A blogger had 400 subscribers to her blog in January. The number of subscribers has grown by a factor of 1.5 every month since t
kompoz [17]
400+600+600+600 which is basically 400+(600•3)
4 0
2 years ago
If cos Θ = square root 2 over 2 and 3 pi over 2 < Θ < 2π, what are the values of sin Θ and tan Θ?
KIM [24]

Answer:

The answer is

sin(\theta)=-\frac{\sqrt{2}}{2}

tan(\theta)=-1

Step-by-step explanation:

we know that

tan(\theta)=\frac{sin(\theta)}{cos(\theta)}

sin^{2}(\theta)+cos^{2}(\theta)=1

In this problem we have

cos(\theta)=\frac{\sqrt{2}}{2}

\frac{3\pi}{2}

so

The angle \theta belong to the third or fourth quadrant

The value of sin(\theta) is negative

Step 1

Find the value of  sin(\theta)

Remember

sin^{2}(\theta)+cos^{2}(\theta)=1

we have

cos(\theta)=\frac{\sqrt{2}}{2}

substitute

sin^{2}(\theta)+(\frac{\sqrt{2}}{2})^{2}=1

sin^{2}(\theta)=1-\frac{1}{2}

sin^{2}(\theta)=\frac{1}{2}

sin(\theta)=-\frac{\sqrt{2}}{2} ------> remember that the value is negative

Step 2

Find the value of tan(\theta)

tan(\theta)=\frac{sin(\theta)}{cos(\theta)}

we have

sin(\theta)=-\frac{\sqrt{2}}{2}

cos(\theta)=\frac{\sqrt{2}}{2}

substitute

tan(\theta)=\frac{-\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}}

tan(\theta)=-1

8 0
2 years ago
Read 2 more answers
12. A cyclist travels 40 km at a speed of x km/h. Find the time
GREYUIT [131]

Answer:

Step-by-step explanation:

distance = rate times time, so

           

           distance

time = --------------

               rate

Here the distance is 40 km and the rate is x.  Then

              40 km

time = --------------  =  (40/x) hr

             x km/hr

If the speed is reduced by 2 km/hr, we get:

              40 km                                            40 km                  40

time = -------------------------------  or time = ----------------------- = --------- hr

             (x km/hr - 2 km/hr)                      (x - 2) (km/hr)       x - 2

The difference between the times is:

 40          40

-------- - --------- = 1 hr          Solve this for the original speed, x

x - 2         x

40x - 40x + 80                                80

-----------------------  =  1 hr     or     ------------ = 1     or 80 = x^2 - 2x

     x(x - 2)                                     x(x - 2)

Rewriting this in standard quadratic form:  x^2 - 2x - 80 = 0

Here a = 1, b = -2 and c = -80, and so the discriminant b^2 - 4ac is:

(-2)^2 - 4(1)(-80) = 324

The solutions are:

   

      -(-2) ± √324       2 ± 18

x = -------------------- = ------------ = 1 ± 9, or 10 (discard the other root)

              2                      2

The original speed was 10 km/hr

7 0
1 year ago
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2x-10/4=3x<br> −10<br> −1<br> 2<br> 11
evablogger [386]

Answer:

<h2>-1</h2>

Step-by-step explanation:

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6 0
2 years ago
At a certain company, the annual winter party is always held on the second of Friday of December. What is the latest possible da
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Answer:

The latest possible date is December, 14th.

Step-by-step explanation:

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