$300 income
$250 + $100 = $350 expenses
$300 - $350 = a loss of $50
x= A ticket
y=b ticket
x+y=500
10x+60y=6000
-------------------
10x+60y=6000
- x+y=500 (*10) ---> 10x+10y=5000
-------------------
10x+60y=6000
- 10x+10y=5000
-------------------
50y=1000
y=1000/50
y=20
b ticket =20
x+y=500
x+20=500
x=500-20
x=480
a ticket=480
answer is the last option ,
Seems to be that the limit to compute is

Consider an arbitrary line through the origin

, so that we rewrite the above as

The value of the limit then depends on the slope

of the line chosen, which means the limit is path-dependent and thus does not exist.
S=small pizzas
p=pasta dinners
s+p=1600
9s+13p=15600
multiply first equaiton by -9 and add to the second one
-9s-9p=-14400
<u>9s+13p=15600 +</u>
0s+4p=1200
4p=1200
divide by 4
p=300
sub back
s+p=1600
s+300=1600
minus 300 both sides
s=1300
1300 small pizzas
300 pasta dinners