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2 years ago

If bc = 8.3 cd = 6.7 and ad = 11.6 find ab to the nearest tenth

1 answer:

3 0

This is going to be tricky to explain over text, so try to bear with me :)

You have the information given above. Let's start with just ad = 11.6 for now. since these are variables, it can also be understood be understood as a times d= 11.6.
Knowing this, we can figure out that d = 11.6/a, when you divide both sides by a.

You now have d, so plug (11.6/a) into cd=6.7. You have to do the same thing you did last time, except this time you are aiming to get c by itself. So, multiply both sides by a/11.6 and you get c = (6.7a)/ 11.6.

Guess what, you know c now! so you put (6.7a)/11.6 in for c in the equation given to you earlier, bc =8.3. The math gets a bit messy here, but you basically solve for b here, which, when you crunch the numbers down, ends up being ~14.3705 divided by a. You are looking for ab, so just multiply both sides by a, and round to the nearest tenth so that you have ab= 14.4

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The fuel cost per hour for running a ship is approximately one half the cube of the speed (measured in knots) plus additional fi

andrezito [222]

Answer:

6 knots

Step-by-step explanation:

Let the speed be v knots

then time taken to cover 500 M = 500 / v hrs

fuel consumption /hr = 216 + 0.5v^3

let F be the fuel consumption for trip

= [500/v][216 + 0.5v^3]

= 500[216/v + 0.5v^2]

dF/dv = 500[ - 216/v^2 + v]

d^2F/d^2v = 500[432/v^3 + 1] , i.e. +ve

so setting dF/dv will give a minima

500[ -216/v^2 + v] = 0

or v = 216/v^2

or v^3 = 216

solving, we get v = [216]^(1/3) = 6 knots

7 0

2 years ago

In an experiment, some diseased mice were randomly divided into two groups. One group was given an experimental drug, and one wa

damaskus [11]

Answer:

D)Yes, because the difference in the means in the actual experiment was more than two standard deviations from 0.

Step-by-step explanation:

We will test the hypothesis on the difference between means.

We have a sample 1 with mean M1=18.2 (drug group) and a sample 2 with mean M2=15.9 (no-drug group).

Then, the difference between means is:

$M_d=M_1-M_2=18.2-15.9=2.3$

If the standard deviation of the differences of the sample means of the two groups was 1.1 days, the t-statistic can be calculated as:

$t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{2.3-(0)}{1.1}=2.09$

The critical value for a two tailed test with confidence of 95% (level of significance of 0.05) is t=z=1.96, assuming a large sample.

This is approximately 2 standards deviation (z=2).

The test statistict=2.09 is bigger than the critical value and lies in the rejection region, so the effect is significant. The null hypothesis would be rejected: the difference between means is significant.

4 0

2 years ago

Mr.Foote placed a cement walk along the side of his house. The walk if 18 inches wide and 32 feet long. What was the cost of the

Sonja [21]

we know that

1 ft-------> is equal to 12 in

step 1

find the area of the walk

18 in wide--------> convert to ft

18/12=1.5 ft

area=1.5*32------> 48 ft²

step 2

find the cost at $2.10 a square foot

multiply 48 ft² by $2.10

48*2.1=$100.80

therefore

the answer is

$100.80

5 0

2 years ago

A submarine is exploring the Pacific Ocean. At 502.5 feet below sea level, the water temperature is 63 1/4 °F. The submarine div

kumpel [21]

-502.5 - 115 = - 617.5

63 1/4 - 2 1/5 =
63 - 2 = 61
1/4 - 1/5 = 5/20 - 4/20 = 1/20
so 63 1/4 - 2 1/5 = 61 1/20

after the sub dove, elevation level is - 617.5 and temp is 61 1/20 F

3 0

2 years ago

Read 2 more answers

It took Amir 2 hours to hike 5 miles. On the first part of the hike, Amir averaged 3 miles per hour. For the second part of the

rjkz [21]

<h2>Answer:</h2>

The equation that will be used to find t is:

$3(2-t)+1.5t=5$