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guapka [62]
2 years ago
3

If titanium is irradiated with light of 233 nm, what is the maximum possible kinetic energy of the emitted electrons?What is the

maximum number of electrons that can be freed by a burst of light whose total energy is 2.00 μJ.
Chemistry
1 answer:
andreyandreev [35.5K]2 years ago
6 0
<h3><u>Answer;</u></h3>

= 2.346 x 10^12 electrons.

<h3><u>Explanation and solution</u>;</h3>

The energy of each photon can be obtained using Planck's equation:  

E = hν = (hc)/λ

   = (6.626 x 10^-34 J s)(2.9979 x 10^8 m/s) / (233 x 10^-9 m)

   = 8.525 x 10^-19 Joules

The maximum kinetic energy for each freed electron will be;

 =  8.525 x 10-19 J - 6.94 x 10^-19 J

  = 1.585 x 10^-19 J

The number of 233 nm photons in the 2.00 x 10-6 J burst of light will be;

= 2.00 x 10^-6 J / 8.525 x 10^-19 J

= 2.346 x 10^12 photons.

Each photon can free at most one electron, so the maximum number of freed electrons will be <u>2.346 x 10^12 electrons.</u>

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