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Natasha_Volkova [10]
2 years ago
12

the surface area of two similar figures are 25 in ^2 and 36 in ^2 if the volume of the smaller figure is 250 in ^3 then what is

the volume of the larger figure?
Mathematics
1 answer:
k0ka [10]2 years ago
8 0

Answer:

432 in^3

Step-by-step explanation:

The ratio of linear dimensions is the square root of the ratio of the areas, so is ...

scale factor = √(36/25) = 6/5

The ratio of volumes is the cube of the ratio of linear dimensions, so is ...

volume ratio = (scale factor)^3 = (6/5)^3 = 216/125

Then the volume of the larger figure is ...

larger volume = (250 in^3)·(216/125) = 432 in^3

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Answer: p= 4

Step-by-step explanation: 4p - 10 = 6

4p-10=6

4p=16

p=4

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A freight train completes its journey of 150 miles 1 hour earlier if its original speed is increased by 5 miles/hour what is the
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<span>A freight train completes its journey of 150 miles 1 hour earlier if its original speed is increased by 5 miles/hour. What is the train’s original speed?
***
let x=original speed
x+5=increased speed
travel time=distance/speed
..
lcd:x(x+5)
150(x+5)-150x=x(x+5)
150x+750-150x=x^2+5x
x^2+5x-750=0
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What is the train’s original speed? 25 mph</span>
7 0
2 years ago
Given: Quadrilateral ABCD is a kite.
Leni [432]

Answer:


Step-by-step explanation:

One

The definition of a kite.

Two

Perpendicular. The diagonals meet at right angles

Three

I don't know if the term is still used, but when I first learned this material (many years ago) we called it the reflexive property.

Four

You found out that <AED = <CED which established that both are right angles. The problem is, you do not have enough information to prove SAS.

AAS is never a dependable reason for proving anything conguent.

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A scale model of a car is 9 inches long. the scale is 1:18. How many inches long is the car it represents?
Rom4ik [11]
1 inch of the model - 18 inches of the car
9 inches of the model - x inches of the car

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2 years ago
According to a study in a medical journal, 202 of a sample of 5,990 middle-aged men had developed diabetes. It also found that m
tekilochka [14]

Answer:

0.0588 = 5.88% probability that a middle-aged man with diabetes is very active

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Has diabetes.

Event B: Is very active.

Probability of having diabetes:

To find this probability, we take in consideration that:

It also found that men who were very active (burning about 3,500 calories daily) were a fourth as likely to develop diabetes compared with men who were sedentary. Assume that one-fifth of all middle-aged men are very active, and the rest are classified as sedentary.

So the probability of developing diabetes is:

x of 4/5 = x of 0.8(not active)

x/4 = 0.25x of 1/5 = 0.2(very active). So

P(A) = 0.8x + 0.25*0.2x = 0.85x

Probability of developing diabetes while being very active:

0.25x of 0.2. So

P(A \cap B) = 0.25x*0.2 = 0.05x

What is the probability that a middle-aged man with diabetes is very active?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.05x}{0.85x} = \frac{0.05}{0.85} = 0.0588

0.0588 = 5.88% probability that a middle-aged man with diabetes is very active

4 0
2 years ago
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