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Art [367]
2 years ago
10

The bar graph shows that life​ expectancy, the number of years newborns are expected to​ live, in a particular region has increa

sed dramatically since ancient times. Find the percent increase in average life expectancy of the region from the Stone Age to 2016.

Mathematics
1 answer:
Serga [27]2 years ago
3 0

Answer:

There was an increase of 176.92 % of life expectancy

Step-by-step explanation:

To find this solution, we need to compare the life expectancy in the Stone age and in 2016

Stone age

26 years. (this represents 100%)

2016

72 years

We apply a rule of three

26 years ------------------100%

72 years --------------------x

(72/26)*100% = 276.92 %

276.92 % - 100% = 176.92 %

There was an increase of 176.92 % of life expectancy

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erastova [34]
I would say the answer is A.
4 0
2 years ago
The archway of the main entrance of a university is modeled by the quadratic equation y = -x^2 + 6x. The university is hanging a
Galina-37 [17]
So the problem ask on which of the following choices you had is the points should the banner be attached in the archway and the best answer among the choices will be letter C. (1.5, 4.87) and (3.5, 4.37). I hope this will help you and feel free to ask for more.
8 0
3 years ago
Read 2 more answers
An online furniture store sells chairs for $200 each and tables for $600 each. Every day, the store can ship a maximum of 32 pie
wolverine [178]

Answer:

If the minimum 13 chair were sold , then the minimum number of Table sold is 14

Step-by-step explanation:

Given as :

The cost of each chair = $ 200

The cost of each table = $ 600

The total number of furniture sold per day = 32

The minimum amount of selling per day = $ 12000

Let the total number of chair = C

The total number of table = T

So , according to question

C + T = 32         .......1

200 C + 600 T = 12000         .......2

Solving eq 1 and 2

200 C + 600 T = 12000

200 × ( C + T ) = 32 × 200

I.e 200 C + 200 T = 6400

or, ( 200 C + 600 T ) - ( 200 C + 200 T ) = 12,000 - 6400

Or, 400 T =  5600

∴  T = \frac{5600}{400}

I.e T = 14

Put The value of T in eq 2

So, 200 C + 600 × 14 = 12000

or , 200 C + 8400 = 12,000

Or, 200 C = 12000 - 8400

Or, 200 C = 3600

∴   C = \frac{3600}{200}

I.e C = 18

The number of chair sold is 18

If the number of chair sold is 13 ,

Then the min number of table sold = 200 × 18 + 600 T = 12000

i.e 600 T = 12000 - 3600

or, 600 T = 8400

∴   T = \frac{8400}{600}

I.e T = 14

Hence if the minimum 13 chair were sold , then the minimum number of Table sold is 14 . Answer

5 0
2 years ago
Exclude leap years from the following calculations. ​(a) Compute the probability that a randomly selected person does not have a
Scrat [10]

Answer:

a) 99.73% probability that a randomly selected person does not have a birthday on March 14.

b) 96.71% probability that a randomly selected person does not have a birthday on the 2 nd day of a month.

c) 98.08% probability that a randomly selected person does not have a birthday on the 31 st day of a month.

d) 92.33% probability that a randomly selected person was not born in February.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

A non-leap year has 365 days.

​(a) Compute the probability that a randomly selected person does not have a birthday on March 14.

There are 365-1 = 364 days that are not March 14. So

364/365 = 0.9973

99.73% probability that a randomly selected person does not have a birthday on March 14.

​(b) Compute the probability that a randomly selected person does not have a birthday on the 2 nd day of a month.

There are 12 months, so there are 12 2nds of a month.

So

(365-12)/365 = 0.9671

96.71% probability that a randomly selected person does not have a birthday on the 2 nd day of a month.

​(c) Compute the probability that a randomly selected person does not have a birthday on the 31 st day of a month.

The following months have 31 days: January, March, May, July, August, October, December.

So there are 7 31st days of a month during a year.

Then

(365-7)/365 = 0.9808

98.08% probability that a randomly selected person does not have a birthday on the 31 st day of a month.

(d) Compute the probability that a randomly selected person was not born in February.

During a non-leap year, February has 28 days. So

(365-28)/365 = 0.9233

92.33% probability that a randomly selected person was not born in February.

6 0
2 years ago
The box plot compares Marta’s and Ani’s diving scores in the first several meets of the season.
astraxan [27]

Answer:

i hope this helps

Step-by-step explanation:

The answer would be A, or "A box-and-whisker plot. The number line goes from 0 to 12, and the box ranges from 4 to 10. A line divides the box at 7.

Step-by-step explanation:

If you plot the data (2, 4, 6, 8, and 12) it looks something like the poor box-and-whisker plot below

      ⊕←    |           Ф           |   →⊕

|---|---|---|---|---|---|---|---|---|---|---|---|

0  1  2  3  4  5  6  7   8  9 10 11 12

Description A describes that exact box-and-whisker plot.

5 0
2 years ago
Read 2 more answers
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