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PolarNik [594]
2 years ago
9

Solve the inequality (n-7)>2n-3. Write the solution in set notation.

Mathematics
2 answers:
Elden [556K]2 years ago
5 0

Answer:

- 4 > n and Notion form : [ -4 , -∞).

Step-by-step explanation:

Given : (n-7)>2n-3.

To find : Solve the inequality.

Solution : We have given

(n - 7) > 2 n - 3.

On adding both sides by 3

n - 7+ 3 > 2n .

n - 4 > 2n .

On subtracting b both sides by n

-4 > 2n -n.

- 4 > n.

So, we can say value of n is less  than - 4 like -5,-6, -7 ........-∞

Notion form : [ -4 , -∞).

Therefore, - 4 > n and Notion form : [ -4 , -∞).

belka [17]2 years ago
3 0

Answer:

n < -4

Step-by-step explanation:

To solve the inequality, use inverse operations.

(n-7) > 2n - 3

n - 7 > 2n - 3

-7 > 2n - n - 3

-7 > n - 3

-7 + 3 > n

-4 > n

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Alice should pick the enlarged-photo with dimensions of 8-inch by 10-inch.

Step-by-step explanation:

Step 1:

In order for a part of the photo to not be cut off, the enlarged photo's dimensions should be of a constant ratio with the original photo's dimensions.

We divide the dimensions of the enlarged-photo with the dimensions of the original photo to check which has a constant ratio.

Step 2:

The original photo was a 4-inch by 5-inch photo.

Option 1 is 7-inch by 9-inch, so the ratios are

\frac{7}{4} = 1.75, \frac{9}{5} = 1.8. The ratios are different so this cannot be the enlarged photo's dimensions.

Option 2 is 8-inch by 10-inch, so the ratios are

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Option 3 is 12-inch by 16-inch, so the ratios are

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2 years ago
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Step-by-step explanation:

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Colin invests £2350 into a savings account. The bank gives 4.2% compound interest for the first 4 years and 4.9% thereafter. How
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To solve this, we are going to use the compound interest formula: A=P(1+ \frac{r}{n} )^{nt}
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For the first 4 years we know that: P=2350, r= \frac{4.2}{100} =0.042, t=4, and since the problem is not specifying how often the interest is communed, we are going to assume it is compounded annually; therefore, n=1. Lest replace those values in our formula:
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Therefore,

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489 to the nearest ten​
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