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Deffense [45]
2 years ago
8

An element with mass 570 grams decays by 26.9% per minute. How much of the element is remaining after 14 minutes, to the nearest

10th of a gram?
Mathematics
2 answers:
Lina20 [59]2 years ago
8 0

Answer:

element remained after 14 minutes = = 7.091 g =~ 10 g

Step-by-step explanation:

After every minute the amount remained will be

(100 - 26.9 ) % i.e. 73.1 %

which is 0.731 times as much as the amount was at the start.

if the number of minutes passed is represented by t the function f(t) represents the mass of element remaining our equation will be

f(t) = 570( 0.731) ^ t

t= 14 minutes

f(14) = 570 ( 0.731) ^ 14

      = 7.091 g =~ 10 g

klio [65]2 years ago
5 0

Answer:

7.1

Step-by-step explanation:

Exponential Functions:

y=ab^x

y=ab  

x

 

a=\text{starting value = }570

a=starting value = 570

r=\text{rate = }26.9\% = 0.269

r=rate = 26.9%=0.269

\text{Exponential Decay:}

Exponential Decay:

b=1-r=1-0.269=0.731

b=1−r=1−0.269=0.731

\text{Write Exponential Function:}

Write Exponential Function:

y=570(0.731)^x

y=570(0.731)  

x

 

Put it all together

\text{Plug in time for x:}

Plug in time for x:

y=570(0.731)^{14}

y=570(0.731)  

14

 

y= 7.091174

y=7.091174

Evaluate

y\approx 7.1

y≈7.1

round

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kari74 [83]

Answer:

1131 pounds.

Step-by-step explanation:

We have been given that an unloaded truck and trailer, with the driver aboard, weighs 30,000 pounds. When fully loaded, the truck holds 26 pallets of cargo, and each of the 18 tires of the fully loaded semi-truck bears approximately 3,300 pounds.

First of all, we will find weight of 18 tires by multiplying 18 by 3,300 as:

\text{Weight of tires of the fully loaded semi-truck}=18\times 3,300

\text{Weight of tires of the fully loaded semi-truck}=59,400

The weight of 26 pallets would be weight of 18 tires minus weight of unloaded truck.

\text{Weight of 26 pallets of cargo}=59,400-30,000

\text{Weight of 26 pallets of cargo}=29,400

Now, we will divide 29,400 by 26 to find average weight of one pallet of cargo.

\text{Average weight of one pallet of cargo}=\frac{29,400}{26}

\text{Average weight of one pallet of cargo}=1130.769230769

\text{Average weight of one pallet of cargo}\approx 1131

Therefore, the average weight of one pallet of cargo is approximately 1131 pounds.

3 0
2 years ago
A small city has three automobile dealerships: a GM dealer selling Chevrolets and Buicks; a Ford dealer selling Fords and Lincol
9966 [12]

Answer:

Event A = { Chevrolet , Buick }

Event B = { Ford , Lincoln }

Event C = { Toyota }

Step-by-step explanation:

- Mutually exclusive events are such that their probability of coming true simultaneously is zero. If we consider set notations we could say.

                             P (A & B) = P (B & C) = P (A & C) = 0

- In our case these events A,B, and C can be defined as:

Answer:

Event A = { Chevrolet , Buick }

Event B = { Ford , Lincoln }

Event C = { Toyota }

4 0
2 years ago
Marilyn has 10 caramels, 12 mints, and 14 bars of dark chocolate in a bag. She picks three items from the bag without replacemen
Gemiola [76]
10+12+14 = 36

12/36 x 11/35 x 14/34 = 11/255

There's your answer.
3 0
2 years ago
Read 2 more answers
Fatima saved $15,000 toward a down payment on a house. She makes $5,375 a month. What is the maximum loan she can take on a hous
Fittoniya [83]

We will use \frac{28}{36} ratio to determine how much can Fatima afford as a loan for her house.

Let gross income of Fatima = $ x

Amount earned by Fatima monthly= $ 5,375

36 % of 5,375=

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Maximum amount that can be paid as a loan monthly = $ 1935

Total money that she can pay yearly for house loan if Fatima allowable money for paying loans is $ 1935=

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She is not allowed for loan for house if the cost of house is any of the four options.

(B) 28 % of $ 5375=

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Maximum amount that Fatima spend on her house monthly= $ 1505

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7 0
2 years ago
Read 2 more answers
A tile mosaic in the shape of a right triangle is used as the corner for a rectangular pathway. The hypotenuse of the mosaic is
Anit [1.1K]

Answer:

The lengths of the sides are 2.2 ft and 4.5 ft

Step-by-step explanation:

Let

a -----> the length of one side of the mosaic

b ----> the length of the other side of the mosaic

c ----> the hypotenuse of the mosaic

we know that

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substitute equation B and equation C in equation A and solve for b

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Find the value of a

a=2b ------> a=2\sqrt{5}=4.5\ ft

therefore

The lengths of the sides are 2.2 ft and 4.5 ft

6 0
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