We know that
if <span>the probability of hitting the blue circle is the same as the probability of hitting the green region
then
the area of the blue circle is equal to the area of the green region
Let
x----> diameter of the blue circle
area of the blue circle=pi*(x/2)</span>²----> (pi/4)*x² m²-----> equation 1
area of the green region=area of the larger circle-area of the blue circle
area of the green region=pi*(1/2)²-(pi/4)*x²
=(pi/4)-(pi/4)*x² m²----> equation 2
equate equation 1 and equation 2
(pi/4)*x²=(pi/4)-(pi/4)*x² -----> divide by (pi/4)---> x²=1-x²
2x²=1-----> x²=1/2----> x=1/√2-----> x=√2/2 m
the diameter of the blue circle is √2/2 m
Answer:
Step-by-step explanation:
D is correct. The idea here is to ensure that the point on the post is equidistant from the bottom of the post (where it meets the ground), which in turn ensures that the angle between ground and post is 90° in at least two places on the ground.
Answer:
Mean and standard deviation of the sampling distribution of the sample proportions are 76 and 0.0427 respectively.
Step-by-step explanation:
The mean for a sample proportion is given by μ = np
n = sample size = 100
p = fraction of the sample proportion that have what is being tested = 76% = 0.76
μ = 0.76 × 100 = 76.
Standard deviation of a sample proportion = σ = √[p(1-p)/n] = √(0.76×0.24/100) = 0.0427