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Artyom0805 [142]
2 years ago
7

Two years ago, Rob bought some shares of a stock, and today those shares have a value of $19.80 each. The price when Rob bought

the stock was 3/4 of the current price per share.
Rob paid ________ per share when he bought the stock two years ago.
Mathematics
1 answer:
navik [9.2K]2 years ago
4 0

Answer:

$14.85 per share

Step-by-step explanation:

(3/4) of the current price = (3/4)·($19.80) = $14.85

Rob paid $14.85 per share.

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What two whole numbers is the quotient between 37 divided by 6
Nitella [24]

Answer:

6 and 7

Step-by-step explanation:

To do this, we need to look at the two closest numbers that are divisible by 6. These are 36 and 42.

36/6=6\\42/6=7

As 37 is between 36 and 42, the quotient must be between 6 and 7

3 0
2 years ago
If your front lawn is 17.0 feet wide and 20.0 feet long, and each square foot of lawn accumulates 1050 new snowflakes every minu
Alexus [3.1K]

Answer: 42.84 kg

Step-by-step explanation: Lawn is 17 ft x 20 ft.

Its area is S = 17 x 20 = 340 ft²

Each ft² of lawn accumulates 1050 snowflakes/min, 1ft² = 1050 s.f./min.

As 1 hour has 60 min, the lawn accumulates 63000/hour →

1050 x 60 = 63000

1ft² = 63000s.f./hour

This way, 340 ft² of lawn will accumulate 21,420,000 s.f/hour →

340 x 63000 = 21420000

As 1 snowflake has 2mg,  21,420,000 will have 42,840,000 mg.

As 1kg = 1,000,000 mg

42,840,000/1,000,000 = 42.84 kg

3 0
2 years ago
Is this relation a function? {(2, 5), (3, 8), (4, 6), (7, 20)} Yes No
SVEN [57.7K]
Yes the x values are all different, if two were the same then it would not be one but in this case it is
4 0
2 years ago
Audrey has x pounds of red grapes and y pounds of
tamaranim1 [39]

Answer:

(2,2)

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Two rectangular properties share a common side. Lot A is 33 feet wide and 42 feet long.
s344n2d4d5 [400]

Answer:

The width of lot B is 11 feet, so option A is correct.

Step-by-step explanation:

Given:

  • Two rectangular properties share a common side.  
  • Lot A is 33 feet wide and 42 feet long.  
  • The combined area of the lots = 1,848 square feet.  

To find:

How many feet wide is Lot B?  

Solution:

we know that, area of a rectangle is length x breadth

Then area of lot A = 33 x 42 = 1386 square feet.

And area of lot B = width x 42

Now, we are given that, total area = 1848  

area of lot A + area of lot B = 1848  

1386 + width x 42 = 1848  

width x 42 = 1848 – 1386  

width x 42 = 462  

width =\frac{42}{462}

width = 11

Hence, the width of lot B is 11 feet, so option A is correct.

7 0
2 years ago
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