Question

Zoe draws ΔABC on the coordinate plane. What is the approximate perimeter of ΔABC

Answer 1

Answer:

Option C is correct.

Step-by-step explanation:

Given: Δ ABC on coordinate plane.

From Coordinate plane, Coordinates are A( 1 , 1 ) , B( 3 , 5 ) and C( 5 , 1 )

We need to find Approximate perimeter of the triangle.

we use the distance formula of two point $(x_1,y_1)\:and\:(x_2,y_2)$

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

So,

$AB=\sqrt{(3-1)^2+(5-1)^2}=\sqrt{(2)^2+(4)^2}=\sqrt{4+16}=\sqrt{20}=4.47\:(approx.)$

$CB=\sqrt{(5-3)^2+(1-5)^2}=\sqrt{(2)^2+(-4)^2}=\sqrt{4+16}=\sqrt{20}=4.47\:(approx.)$

$AC=\sqrt{(5-1)^2+(1-1)^2}=\sqrt{(4)^2+(0)^2}=\sqrt{16}=4$

Thus, Perimeter = AB + AC + CB = 4.47 + 4.47 + 4 = 12.94 units

Therefore, Option C is correct.

Answer 2

B. 12 units because when you add the lengths together you get 12