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malfutka [58]
2 years ago
14

How many milliliters of 0.258M NaOH are required to completely neutralize 2.00 g of acetic acid HC2H3O2?

Chemistry
1 answer:
madam [21]2 years ago
8 0

Answer:

0.129 L = 129.0 mL.

Explanation:

  • NaOH neutralizes acetic acid (CH₃COOH) according to the balanced reaction:

<em>NaOH + CH₃COOH → CH₃COONa + H₂O.  </em>

  • According to the balanced equation: 1.0 mole of NaOH will neutralize 1.0 mole of CH₃COOH.  

<em>no. of moles of CH₃COOH = mass/molar mass </em>= (2.0 g)/(60 g/mol) = <em>0.033 mole.  </em>

<em> </em>

  • For NaOH:

no. of moles = (0.258 mol/L)(V)

  • At neutralization: no. of moles of NaOH = no. of moles of CH₃COOH  

∴ (0.258 mol/L)(V) = 0.033 mole

<em>∴ The volume of NaOH</em> =  (0.033 mole)/(0.258 mol/L) = <em>0.129 L = 129.0 mL.</em>

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Which choice(s) correctly rank(s) the bonds in terms of increasing polarity?
Marina CMI [18]

Answer:

(II) only correctly rank the bonds in terms of increasing polarity.

Explanation:

Bond polarity is proportional to difference in electronegativity between bonded atoms.

Atoms    Electronegativity          Bond        Electronegativity difference

Cl                          3.0                       Cl-F                      1.0

Br                          2.8                       Br-Cl                     0.2

F                            4.0                       Cl-Cl                      0

H                            2.1                       H-C                       0.4

C                            2.5                       H-N                       0.9

N                             3.0                      H-O                       1.4

O                             3.5                      Br-F                       1.2

I                               2.7                      I-F                         1.3

Si                             1.9                      Cl-F                       1.0  

P                              2.2                      Si-Cl                      1.1

                                                          Si-P                        0.3

                                                          Si-C                        0.6

                                                           Si-F                        2.1

So, clearly, order of increasing polarity : O-H > N-H > C-H

So, (II) only correctly rank the bonds in terms of increasing polarity

4 0
2 years ago
The molar concentration of a sugar solution in an open beaker has been determined to be 0.3M. Calculate the solute potential at
antoniya [11.8K]

Answer:

- 7.48

Explanation:

Given:

Concentration of the sugar solution, C = 0.3 M

Temperature, T = 27° C = 273 + 27 = 300 K

Now,

The solute potential is given as:

solute potential = - iCRT

where,

i is the number of particles the particular molecule will make in water

i = 1 for sugar

R is the universal gas constant = 0.0831 liter bar/mole-K

on substituting the respective values, we get

solute potential = - 1 × 0.3 × 0.0831 × 300

or

The solute potential = - 7.479 ≈ - 7.48

8 0
2 years ago
A sample of pure iron has a mass of 5.00 g. Calculate its volume.
olga55 [171]
<span>It's volume is 0.48 cm3Specific </span>
3 0
2 years ago
An empty beaker is weighed and found to weigh 23.1 g. Some potassium chloride is then added to the beaker and weighed again. The
GuDViN [60]

Answer:Mass of Potassium chloride =1.762g

Explanation:

Mass of empty beaker = 23.100 g

Mass of beaker with Potassium chloride = 24.862g

Mass of Potassium chloride = Final weight - initial weight = Mass of beaker with Potassium chloride  - Mass of empty beaker = 24.862-23.100 = 1.762g

8 0
2 years ago
how do i get the bond dissociation energy to break 7 C-H bond(s) in 1 mole of propane (CH₃CH₂CH₃) molecules is
stiv31 [10]

Answer:

2877kJ/mol

Explanation:

Hello.

In this case, since the bond energy per C-H bond is 411 kJ/mol and we of course avoid the C-C bond since we are asked to compute the energy to break 7 C-H bonds, the 411 kJ/mol are multiplied by 7 as shown below:

7*411kJ/mol\\\\=2877kJ/mol

Thus, we obtain the required bond dissociation energy. Note that propane CH₃-CH₂-CH₃ has seven C-H bonds; 3 from the first CH₃, two from the CH₂ and 3 from the last CH₃.

Best regards.

6 0
2 years ago
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