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2 years ago

How many milliliters of 0.258M NaOH are required to completely neutralize 2.00 g of acetic acid HC2H3O2?

Chemistry

1 answer:

madam [21]2 years ago

8 0

Answer:

0.129 L = 129.0 mL.

Explanation:

NaOH neutralizes acetic acid (CH₃COOH) according to the balanced reaction:

<em>NaOH + CH₃COOH → CH₃COONa + H₂O. </em>

According to the balanced equation: 1.0 mole of NaOH will neutralize 1.0 mole of CH₃COOH.

<em>no. of moles of CH₃COOH = mass/molar mass </em>= (2.0 g)/(60 g/mol) = <em>0.033 mole. </em>

For NaOH:

no. of moles = (0.258 mol/L)(V)

At neutralization: no. of moles of NaOH = no. of moles of CH₃COOH

∴ (0.258 mol/L)(V) = 0.033 mole

<em>∴ The volume of NaOH</em> = (0.033 mole)/(0.258 mol/L) = <em>0.129 L = 129.0 mL.</em>

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Cobalt-60 is produced by a three reaction process involving neutron capture, beta-emission, and neutron capture. The initial rea

Dima020 [189]

Answer : The correct option is, (C) $^{58}\textrm{Fe}$

Explanation :

Neutron capture : In this decay process, an atomic nucleus and one or more number of neutrons collide and combine to form a heavier nucleus. The mass number changes in this process.

The neutron capture equation is represented as,

$_Z^A\textrm{X}+_{0}^1\textrm{n}\rightarrow _{Z}^{A+1}\textrm{X}+\gamma$

(A is the atomic mass number and Z is the atomic number)

Beta emission or beta minus decay : It is a type of decay process, in which a neutrons gets converted to proton, an electron and anti-neutrino. In this the atomic mass number remains same.

The beta minus decay equation is represented as,

$_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0e$

(A is the atomic mass number and Z is the atomic number)

As per question, the cobalt-60 is produced by a three reaction process involving neutron capture, beta-emission, and neutron capture.

Process 1 : Neutron capture.

$_{26}^{58}\textrm{Fe}+_{0}^1\textrm{n}\rightarrow _{26}^{59}\textrm{Fe}+\gamma$

Process 2 : Beta emission.

$_{26}^{59}\textrm{Fe}\rightarrow _{27}^{59}\textrm{Co}+_{-1}^0e$

Process 3 : Neutron capture.

$_{27}^{59}\textrm{Co}+_{0}^1\textrm{n}\rightarrow _{26}^{60}\textrm{Co}+\gamma$

From this we conclude that, the initial reactant in the production of cobalt-60 is $_{26}^{58}\textrm{Fe}$

Hence, the correct option is, (C) $^{58}\textrm{Fe}$

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2 years ago

Three compounds containing potassium and oxygen are compared. Analysis shows that for each 1.00 g of O, the compounds have 1.22

kicyunya [14]

<span>The law of proportion states that elements combine in whole number ratios. The gram readings for K are multiples of each other, both in grams and moles.
Let us compare the ratios:
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<span>4.89 grams/2.44 grams = 2</span>

<span>Therefore, Potassium always combines with Oxygen in a ratio of 2 is to 1.</span>

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2 years ago

Mr. Smith is hyperglycemic with a blood glucose level of 300mg/ml of blood. Explain how homeostasis would regulate his glucose l

aleksley [76]

Answer:

When the animal has eaten food and the blood glucose level in the body increases. The pancreas cells in the body detects the increase in the blood glucose which leads to increase the insulin hormone.

This decreases the blood glucose level in the level. This is how the negative feedback works in the body if the level of glucose increases.

Negative feedback is the way by which the body maintains homeostasis and maintains equilibrium in the body.

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2 years ago

What is the formal charge on the nitrogen in hydroxylamine, h2noh?

andrew11 [14]

<h3>Answer:</h3>

Formal Charge on Nitrogen is "Zero".

<h3>Explanation:</h3>

Formal Charge on an atom in molecules is calculated using following formula;

Formal Charge = [# of Valence e⁻s] - [e⁻s in lone pairs + 1/2 # of Bonding e⁻s]

As shown in attached picture of Hydroxylamine, Nitrogen atom is containing two electrons in one lone pair of electrons and six electrons in three single bonds with two hydrogen and one oxygen atom respectively.

Hence,

Formal Charge = [5] - [2 + 6/2]

Formal Charge = [5] - [2 + 3]

Formal Charge = 5 - 5

Formal Charge = 0 (zero)

Hence, the formal charge on nitrogen atom in hydroxylamine is zero.

5 0

2 years ago

How many milliliters of 0.02 M HCl are needed to react completely with 100 mL of 0.01 M NaOH?

serious [3.7K]

The reaction of HCl and NaOH is HCl + NaOH = NaCl + H2O. So the mole number of HCl and NaOH is equal. So the volume of HCl =0.01*0.1/0.02=0.05 L =50 ml. So the answer is D).

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2 years ago

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