Question

Write an equation in slope-intercept form of the line perpendicular to y = 3x + 4 that passes through the point (3, 4).

Answer 1

Answer:

The correct answer option is D. $y= -\frac{1}{3} x+5$.

Step-by-step explanation:

We are to find the equation of a line which is perpendicular to the following line and passes through the point (3, 4):

$y = 3x + 4$

We know that an equation perpendicular to another equation has a slope which is the negative reciprocal of the first equation.

So our required slope is $-\frac{1}{3}$

Finding the y-intercept:

$y=mx+c$

$4=-\frac{1}{3}(3)+c$

$c=5$

Therefore, the equation of the line perpendicular to $y = 3x + 4$ and passing through the point (3, 4) is $y= -\frac{1}{3} x+5$.

Answer 2

Answer:

(D)  y= -1/3 x +5

Step-by-step explanation:

Perpendicular lines have gradients that multiply to give -1

Equation given, y=3x+4

gradient m₁=3

Finding m₂ we know m₁×m₂= -1

Thus m₁×m₂=-1 ⇒ 3×m₂=-1

m₂= -1/3

Equation of new line passing through points (3,4) with gradient m₂=-1/3 will be;

Δy/Δx =m₂

(y-4)/(x-3) = - 1/3

3(y-4)= -1(x-3)

3y-12= -x+3

3y=-x+3+12

3y/3= -x/3 + 15/3

y= -1/3 x +5