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Nonamiya [84]
2 years ago
8

A farmer can spend no more than $4,000 on fertilizer and seeds. The fertilizer costs $2 per pound and seeds cost $20 per pound.

To summarize the situation, the farmer writes the inequality: 2f + 20s ≤ 4,000, where f is the number of pounds of fertilizer and s is the number of pounds of seeds. Which graph's shaded region shows the possible combinations of fertilizer and seeds the farmer can buy?

Mathematics
2 answers:
lilavasa [31]2 years ago
7 0

Answer:

The graph in the attached figure

Step-by-step explanation:

Let

f -----> the number of pounds of fertilizer

s ----> the number of pounds of seeds

we know that

The inequality that represent the situation is

2f+20s\leq 4,000

using a graphing tool

see the attached figure

The solution is the triangular shaded area

Dmitriy789 [7]2 years ago
4 0

Answer:

it is the 2nd graph

Step-by-step explanation:

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Oduvanchick [21]

Answer:

7

Step-by-step explanation:

7

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1 year ago
To make a profit, a company’s revenue must be greater than its operating costs. The company’s revenue is modeled by the expressi
myrzilka [38]
Revenue = 7.5x - 100
Operation Costs = 5.8x + 79.86

To break even, operation cost = Revenue
⇒ 7.5x - 100 = 5.8x + 79.86
7.5x = 5.8x + 179.86 (Add 100 to both sides)

7.5x - 5.8x = 179.86
1.7x = 179.86
x = 105.8

This implies that the company will need to sell at least 106 items to make a profit.

The inequality that will determine the number of items at need to be sold to make a profit is x ≥ 106

The solution to the inequality is as follows

Revenue = 7.5x - 100
if x =106
Revenue = 7.5(106) - 100
Revenue = 695

Operational Cost = 5.8x + 79.86
if x = 106
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Operational Cost = 694.66

Profit ≥ (695 - 694.66)
Profit ≥ 0.34

The company must sell at least 106 items to make a profit.
7 0
2 years ago
Read 2 more answers
A circle fits inside a semicircle of diameter 24mm
patriot [66]

Answer:

The shaded are is 113\ mm^{2}

Step-by-step explanation:

we know that

The shaded area is equal to the area of the semicircle minus the area of the circle inside the semicircle

step 1

Find the area of semicircle

The area of semicircle is equal to

A=\frac{1}{2}\pi r^{2}

where

r=24/2=12\ mm ----> the radius is half the diameter

substitute

A=\frac{1}{2}\pi(12)^{2}=72\pi\ mm^{2}

step 2

Find the area of the circle inside the semicircle

The area of circle is equal to

A=\pi r^{2}

where

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substitute

A=\pi(6)^{2}=36\pi\ mm^{2}

step 3

Find the shaded area

72\pi\ mm^{2}-36\pi\ mm^{2}=36\pi\ mm^{2}

assume

\pi=3.14

36(3.14)=113.04\ mm^{2}

3 significant figures is

113\ mm^{2}

6 0
2 years ago
There are 135 people in a sport centre. 73 people use the gym. 59 people use the swimming pool. 31 people use the track. 19 peop
Anna71 [15]

Answer:

1/9

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31:track

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4/36=1/9

Hope this helps!!!

6 0
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Paul bakes loaves of bread and bread rolls in the ratio of 2:5. If he bakes 750 bread rolls, how many loaves will he bake? A rec
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Paul bakes 300 bread loaves. I don’t know the question you’re asking for the second question.
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2 years ago
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