A farmer can spend no more than $4,000 on fertilizer and seeds. The fertilizer costs $2 per pound and seeds cost $20 per pound.
To summarize the situation, the farmer writes the inequality: 2f + 20s ≤ 4,000, where f is the number of pounds of fertilizer and s is the number of pounds of seeds. Which graph's shaded region shows the possible combinations of fertilizer and seeds the farmer can buy?
2 answers:
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Answer:
(1) Therefore, a 90% confidence interval for the proportion of Americans who decide to not go to college because they cannot afford it is [0.4348, 0.5252].
(2) We can be 90% confident that the proportion of Americans who choose not to go to college because they cannot afford it is contained within our confidence interval
(3) A survey should include at least 3002 people if we wanted the margin of error for the 90% confidence level to be about 1.5%.
Step-by-step explanation:
We are given that a simple random sample of 331 American adults who do not have a four-year college degree and are not currently enrolled in school, 48% said they decided not to go to college because they could not afford school.
Firstly, the pivotal quantity for finding the confidence interval for the population proportion is given by;
P.Q. = ~ N(0,1)
where, = sample proportion of Americans who decide to not go to college = 48%
n = sample of American adults = 331
p = population proportion of Americans who decide to not go to
college because they cannot afford it
<em>Here for constructing a 90% confidence interval we have used a One-sample z-test for proportions.</em>
<em />
<u>So, 90% confidence interval for the population proportion, p is ;</u>
P(-1.645 < N(0,1) < 1.645) = 0.90 {As the critical value of z at 5% level
of significance are -1.645 & 1.645}
P(-1.645 < < 1.645) = 0.90
P( <
<
) = 0.90
P( < p <
) = 0.90
<u>90% confidence interval for p</u> = [ ,
]
= [ ,
]
= [0.4348, 0.5252]
(1) Therefore, a 90% confidence interval for the proportion of Americans who decide to not go to college because they cannot afford it is [0.4348, 0.5252].
(2) The interpretation of the above confidence interval is that we can be 90% confident that the proportion of Americans who choose not to go to college because they cannot afford it is contained within our confidence interval.
3) Now, it is given that we wanted the margin of error for the 90% confidence level to be about 1.5%.
So, the margin of error =
= 54.79
n =
n = 3001.88 ≈ 3002
Hence, a survey should include at least 3002 people if we wanted the margin of error for the 90% confidence level to be about 1.5%.
I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
PLEASE SEE ATTACHED IMAGE.
For this case the area is given by:
A = (22 + x) * (28 + x) = 722
Rewriting we have:
616 + 22x + 28x + x ^ 2 = 722
x ^ 2 + 50x + 616 - 722 = 0
x ^ 2 + 50x - 106 = 0
Solving the polynomial we have:
x1 = 2.04
x2 = -52.04
We take the positive root:
x = 2.04 inches:
Answer:
The width of the border to the nearest inch is:
x = 2inches
PLEASE SEE ATTACHED IMAGE.
For this case the area is given by:
A = (22 + x) * (28 + x) = 722
Rewriting we have:
616 + 22x + 28x + x ^ 2 = 722
x ^ 2 + 50x + 616 - 722 = 0
x ^ 2 + 50x - 106 = 0
Solving the polynomial we have:
x1 = 2.04
x2 = -52.04
We take the positive root:
x = 2.04 inches:
Answer:
The width of the border to the nearest inch is:
x = 2inches