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Jlenok [28]
2 years ago
12

There are two calculus classes at your school. Both classes have a class average of 75.5. The first class has a standard deviati

on of 10.2 and the second has a standard deviation of 22.5. How do the classes compare?
Question 3 options:

They are about the same.


The second class has higher grades than the first.


The first class' scores are closer together and the second's score are more spread out.


The second class' scores are closer together and the first's score are more spread out.
Mathematics
1 answer:
romanna [79]2 years ago
6 0

Answer:

idk sorry

Step-by-step explanation:

You might be interested in
If x% of four-digit numbers have a repeated digit (the repeated digits do not need to be adjacent), then what is x? Express your
joja [24]

Answer

It is a 4 digit number but 1 digit (exactly one digit) is repeated just once.

So 3 digits out of 10 have to be chosen.

There are 10C3 = 120 ways to do this.

say the digits chose are 5,6 and 9, they can be in any order and there are 3! possible orders =6 orders.

So so far that is 120*6=720 ways to get a 3 digit number where the digits are all different.

But we want a 4 digit number.

One digit has to be repeated there are 3 possibilities so that is 720*3 = 2160 posibilities.

But there are 4 postions that extra number can be put in. So that is 2160*4=8640 numbers

But I have double counted because 1434 is the same if I swap the 4s around so I have to halve this answer

8640/2 = 4320

So the number of favourable outcomes is 4320.

Altogether there are 10*10*10*10 = 10000 4 digit numbers (if they are allowed to start with 0)

so the prob of getting just one digit repeated once is 4320/10000 = 0.4320 = 43.2%

Do you understand now?

You will need to write your query on this thread but also send me a private message with the address of this thread attached. Otherwise I will not see it.

If you do have a query try to ask a specific question.

Anyway I hope that you understand

8 0
2 years ago
Sameer polled a random selection of 120 of the 250 workers at his office to determine whether they were satisfied with their off
jeka57 [31]
The margin of error can be calculated with the formula:

ME = z · √(p(1-p)/n)

where:
p = sample proportion
n = sample size
z = z-score

In your case:
p = 90 / 120 = 0.75

ME = 2.58 · √(0.75·0.25/120)
      = 0.10
      = 10%

The margin of error will be 10%.
6 0
2 years ago
Read 2 more answers
which geometric series represents 0.4444... as a fraction? a) 1/4, 1/40, 1/400, 1/4,000 b) 1/40, 1/400, 1/4,000, 1/40,000 c) 4/1
xenn [34]

Answer: \frac{4}{10}+\frac{4}{100}+\frac{4}{1,000}+\frac{4}{10,000}


Step-by-step explanation:

The given geometric series are:

a)\frac{1}{4}+\frac{1}{40}+\frac{1}{400}+\frac{1}{4,000}

on simplifying in decimals, we get

0.25+0.025+0.0025+0.00025=0.27775\neq0.4444

b) \frac{1}{40}+\frac{1}{400}+\frac{1}{4,000}+\frac{1}{40,000}

on simplifying in decimals, we get

0.025+0.0025+0.00025+0.000025=0.027775\neq0.4444

c)\frac{4}{10}+\frac{4}{100}+\frac{4}{1,000}+\frac{4}{10,000}

on simplifying in decimals, we get

0.4+0.04+0.004+0.0004=0.4444

Thus, this geometric series represent 0.4444.

d)\frac{1}{10}+\frac{1}{100}+\frac{1}{1,000}+\frac{1}{10,000}

on simplifying in decimals, we get

0.1+0.01+0.001+0.0001=0.1111\ \neq0.4444

7 0
2 years ago
Read 2 more answers
Do oddsmakers believe that teams who play at home will have home field advantage? Specifically, do oddsmakers give higher point
vladimir2022 [97]

Answer:

Option 3 is correct.

The data do not provide sufficient evidence to reject H0; thus, we cannot conclude that the mean point spread of home games is higher than that of away games.

Step-by-step explanation:

Before anything else, we first give the null and alternative hypothesis for this question.

Null hypothesis would be that there isn't significant evidence to conclude that the mean point spread of home games is higher than that of away games.

H0: µ1 = µ2

And the alternative hypothesis would be that there is significant evidence to conclude that the mean point spread of home games is higher than that of away games.

Ha: μ1 > μ2

The data from the output of the analysis of the hypothesis test is missing from the question. It was obtained online and is attached to this solution of the question.

The table consists of the difference, the sample mean, the standard error of the mean, degree of freedom, the test statistic and most importantly, the p-value. It is the p-value that absolutely gives us the concluding statement of the hypothesis testing.

When the significance level for a test isn't provided, the convention is usually to use 5% significance.

Interpretation of p-value

When the (p-value > significance level), we fail to reject the null hypothesis and when the (p-value < significance level), we reject the null hypothesis and accept the alternative hypothesis.

So, for this question, significance level = 0.05

p-value = 0.4351

0.4351 > 0.05

Hence,

p-value > significance level

This means that we fail to reject the null hypothesis & say that 'The data do not provide sufficient evidence to reject H0; thus, we cannot conclude that the mean point spread of home games is higher than that of away games'.

Hope this Helps!!!

7 0
2 years ago
If h(x) = 5 x and k(x)=1/x, which expression is equivalent to (koh)(x)?
Lyrx [107]
May be there is an operator missing in the first function, h(x). I will solve this in two ways, 1) as if the h(x) = 5x and 2) as if h(x) = 5 + x

1) If h(x) = 5x and k(x) = 1/x

Then (k o h) (x) = k ( h(x) ) = k(5x) = 1/(5x)

2) If h(x) = 5 + x and k (x) = 1/x

Then (k o h)(x) =k ( h(x) ) = k (5+x) =  1 / [5 + x]
4 0
2 years ago
Read 2 more answers
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