Answer:
B) The rates of ATP production and carbon dioxide production would both increase.
Explanation:
The citric acid cycle is the second stage of aerobic cellular respiration. It includes complete oxidation of acetyl CoA into CO2 and H2O. During the citric acid cycle, NAD and FAD serve as electron acceptors. Reduction of these reducing powers forms NADH and FADH2 which in turn enter the electron transport chain for their oxidation and drive the process of as many as 32 ATP molecules by oxidative phosphorylation. On the other hand, fermentation forms of 2 ATP molecules and a few or no CO2 molecules.
Therefore, if one of the eight intermediates of the citric acid cycle is added to the medium, the yeast cells would perform aerobic cellular respiration and would form more CO2 and ATP molecules than the ones formed during the process of fermentation.
Natural selection would probably favor different varieties in the different islands. In other words, beaks changed as the birds developed different tastes for fruits, seeds, or insects picked from the ground or cacti (due to lack of food resources). Long, pointed beaks made some of them more fit for picking seeds out of cactus fruits.
Hope This Helps!
It seems to me the correct answer would be nucleous
Answer:
Genetic diversity: Some individuals in a population of wild rabbits are resistant to a new disease.
Ecosystem diversity: If the population of wild rabbits decreases, a bobcat can switch its diet to squirrels or woodchucks.
Species diversity: Populations of wild rabbits from a forest and from a neighboring meadow can interbreed, which increases variation.
Biodiversity of an ecosystem is usually explored by three diversities which are responsible for ecosystem stability they are : genetic diversity, ecosystem diversity and species diversity.
Genetic diversity is the variety of genes within a population of species. Each species consists of individuals bearing different genetic composition. Some individuals in a population of wild rabbits are resistant to a new disease because they exhibit genetic diversity within the population as a consequence some individuals exhibit genes which protect them against new disease.
Species diversity is the variety of species within an ecosystem. Populations of wild rabbits from a forest and from a neighboring meadow can interbreed, which increases variation is an example of species diversity. The wild rabbits from a forest and a neighboring meadow are two species living in an ecosystem stating the diversity of species in an ecosystem.
Ecosystem diversity is the variety of ecosystems in a given region.If the population of wild rabbits decreases, a bobcat can switch its diet to squirrels or woodchucks is an example of ecosystem diversity because in an ecosystem there is interaction of organisms as predator prey relationship. This example is also relating with predator prey relationships in an ecosystem.
Answer:
Explanation:
To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.
The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.
So, en the exposed example:
- J and K are autosomal genes
- J and K are separated by 60 M.U.
- 60 M.U. means that there is 60% of recombination.
Cross) J K / j k x j k / j k
Gametes) JK Parental jk, jk, jk, jk
jk Parental
Jk Recombinant
jK Recombinant
One map unit equals 1% of recombination frequency. This means that every 100 meiotic products, one of them is a recombinant one.
1 M.U. -------------- 1% recombination
60 M.U. ------------ 60% recombination
30% Jk + 30% jK
100 M.U. - 60 M.U. = 40 M.U.
40M.U.--------------40 % Parental (Not recombinant)
20% JK + 20% jk
Punnet Square) JK jk Jk jK
jk JK/jk jk/jk Jk/jk jK/jk
J K / j k = 20%
j k / j k = 20%
J k / j k = 30%
j K / j k = 30%
