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Scorpion4ik [409]

1 year ago

9

You have 128 ounces of milk and drink 16 ounces per day. What algebraic expression models the amount of milk you have after d da

ys?

1 answer:

Viktor [21]1 year ago

3 0

128-16(d)=your amount of milk you have

plz rate as brainliest also add me as a friend if you want

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A 2-column table with 6 rows. The first column is labeled miles driven with entries 27, 65, 83, 109, 142, 175. The second column

Helen [10]

Answer:

1) The linear regression model is y = -0.0348·x + 13.989

2) The correlation coefficient is -0.0725

3) The strength of the model is strong - association

Step-by-step explanation:

1)

X Y XY X²

27 13 351 729

65 12 780 4225

83 11 913 6889

109 10 1090 11881

142 9 1278 20164

175 8 1400 30625

∑ 601 63 5812 74513

From y = ax + b, we have

$a = \frac{n\sum xy - \sum x\sum y }{n\sum x^{2}-\left (\sum x \right )^{2}} = \frac{6 \times 5812 - 601 \times 63}{6 \times 74513-601^{2}} = - 0.0348$

b = 1/n(∑y -a∑x) = 1/6(63 - (0.0348)×601) = 13.989

Therefore, the linear regression model is y = -0.0348·x + 13.989

2)

$r = \frac{n\sum xy - \sum x\sum y }{\sqrt{[n\sum x^{2}-\left (\sum x \right )^{2}] [n\sum y^{2}-\left (\sum y \right )^{2}]}} = \frac{6 \times 5812 - 601 \times 63}{\sqrt{[6 \times 74513-601^{2}] [6 \times 3969 - 63^2]} } = - 0.0725$

3) The strength is - association.

5 0

2 years ago

Read 2 more answers

Evaluate the expression 2.1 + (–3.7h) + 1.9h – 1.4

zubka84 [21]

2.1 + (-3.7h) + 1.9h - 1.4
2.1 - 3.7h + 1.9h - 1.4
2.1 - 1.8h - 1.4
0.7 - 1.8h

the simplified form is 0.7 - 1.8h

5 0

1 year ago

A duck's mass at birth was 0.05 kilogram. The duck gained approximately 0.042 kilogram each week. After how many weeks is the du

Alex_Xolod [135]

Given that the first mass of the duck is 0.05 kg and it gains weight at a rate of 0.042 kg/week, the equation that would represent this scenario is,
y = 0.05 + 0.042x
where y is weight and x is the number of weeks. To determine the number of weeks in which the duck's mass becomes 0.890,
0.890 = 0.05 + 0.042x
The value of x from the equation is 20.

4 0

2 years ago

Problem 5 (4+4+4=12) We roll two fair 6-sided dice. Each one of the 36 possible outcomes is assumed to be equally likely. 1) Fin

tekilochka [14]

Answer:

1

$p(b) = \frac{1}{6}$

2

$p(k) = \frac{1}{3}$

3

$P(a) = \frac{1}{3}$

Step-by-step explanation:

Generally when two fair 6-sided dice is rolled the doubles are

(1 1) , ( 2 2) , (3 3) , (4 4) , ( 5 5 ), (6 6)

The total outcome of doubles is N = 6

The total outcome of the rolling the two fair 6-sided dice is

n = 36

Generally the probability that doubles (i.e., having an equal number on the two dice) were rolled is mathematically evaluated as

$p(b) = \frac{N}{n}$

$p(b) = \frac{6}{36}$

$p(b) = \frac{1}{6}$

Generally when two fair 6-sided dice is rolled the outcome whose sum is 4 or less is

(1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (3, 1)

Looking at this outcome we see that there are two doubles present

So

The conditional probability that doubles were rolled is mathematically represented as

$p(k) = \frac{2}{6}$

$p(k) = \frac{1}{3}$

Generally when two fair 6-sided dice is rolled the number of outcomes that would land on different numbers is L = 30

And the number of outcomes that at least one die is a 1 is W = 10

So

The conditional probability that at least one die is a 1 is mathematically represented as

$P(a) = \frac{W}{L}$

=> $P(a) = \frac{10}{30}$

=> $P(a) = \frac{1}{3}$

3 0

1 year ago

Paula, a college student, earned $3,600 one summer. During the following semester, she spent $2,500 for tuition, $650 for rent,

Softa [21]

So to get the $ spent on misc items, just add up the other expenses and subtract it from 3600:

$2500+650+430=3580\\ \\ 3600-3580=\$ 20$

Now to put them into fractions.

Tuition: $\frac{2500}{3600}=\frac{25}{36}$

Rent: $\frac{650}{3600}=\frac{65}{360}$

Food: $\frac{430}{3600}=\frac{43}{360}$

Misc: $\frac{20}{3600}=\frac{1}{180}$

8 0

1 year ago

Read 2 more answers