Use the FOIL method (First, Outside, Inside, Last)
6r(-8r) = -48r²
6r(-3) = -18r
-1(-8r) = 8r (note: two negatives multiplied together = positive answer)
-1(-3) = 3
-48r² - 18r + 8r + 3
Combine like terms:
-48r² - 18r + 8r + 3
-48r² - 10r + 3
-48r² - 10r + 3 is your answer
hope this helps
A wall is in the shape of a trapezoid and it can be divided into a rectangle and a triangle. A triangle is with angles 45°- 45° - 90°. The hypotenuse of that triangle is 13√2 ft.Using the 45° - 45° - 90° theorem, sides of that triangle are in the proportion:x : x : x√2, and since that x√2 = 13√2 ( hypotenuse ), x = 13.Therefore h = 13 ft.We can check it: c² = 13² + 13²,c² = 169 + 169c² = 338c = √ 338 = 13√2Answer: h = 13 ft
Answer:
The wedge cut from the first octant ⟹ z ≥ 0 and y ≥ 0 ⟹ 12−3y^2 ≥ 0 ⟹ 0 ≤ y ≤ 2
0 ≤ y ≤ 2 and x = 2-y ⟹ 0 ≤ x ≤ 2
V = ∫∫∫ dzdydx
dz has changed from zero to 12−3y^2
dy has changed from zero to 2-x
dx has changed from zero to 2
V = ∫∫∫ dzdydx = ∫∫ (12−3y^2) dydx = ∫ 12(2-x)-(2-x)^3 dx =
24(2)-6(2)^2+(2-2)^4/4 -(2-0)^4/4 = 20
Step-by-step explanation:
To solve this problem, we need to know that
arc length = r θ where θ is the central angle in radians.
We're given
r = 6 (units)
length of minor arc AB = 4pi
so we need to calculate the central angle, θ
Rearrange equation at the beginning,
θ = (arc length) / r = 4pi / 6 = 2pi /3
Answer: the central angle is 2pi/3 radians, or (2pi/3)*(180/pi) degrees = 120 degrees
Angle AQB is x = 90
Angle ASB is x = 90
Angle ALB is x = 90
Angle ATB is x = 90
Angle ARB is x = 90
<span>BWD is x < 90</span>
