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Damm [24]
2 years ago
14

Which of the following is the product of the rational expressions shown below x+2/x-4•3x/x+4

Mathematics
1 answer:
Doss [256]2 years ago
3 0

Answer:

Final answer is \frac{3x^2+6x}{x^2-16}.

Step-by-step explanation:

Given rational expressions are \frac{x+2}{x-4} and \frac{3x}{x+4}.

Now we need to find about what is the product of given rational expressions.

to multiply the rational expressions, we simply multiply numerator with numerator. Then multiply denominator with denominator.

\frac{x+2}{x-4}\cdot\frac{3x}{x+4}

=\frac{\left(x+2\right)\cdot3x}{\left(x-4\right)\cdot\left(x+4\right)}

=\frac{3x^2+6x}{x^2+4x-4x-16}

=\frac{3x^2+6x}{x^2-16}

Hence final answer is \frac{3x^2+6x}{x^2-16}.

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Find the hcf of 144 and 180. if it is expressed in the form 13m-3, find the value of m​
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Answer:

Step-by-step explanation:

To find the HCF of 144 and 180

By using product of prime method

Firstly express 144 as a product of it prime and express 180 as a product of it prime

140=2×2×2×2×3×3

180=2×2×3×3×5

Common factor =2×2×3×3

36

in term of m

m=36

13m-3

To find m

Substitute for m when m=36

13(36)-3=

465

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kherson [118]

The factorization of the expression of 43x³ + 216y³ is

(7x + 6y)(49x² - 42xy + 36y²)

Step-by-step explanation:

The sum of two cubes has two factors:

1. The first factor is \sqrt[3]{1st} + \sqrt[3]{2nd}

2. The second factor is ( \sqrt[3]{1st} )² - ( \sqrt[3]{1st} ) ( \sqrt[3]{2nd} ) + ( \sqrt[3]{2nd} )²

Ex: The expression a³ + b³ is the sum of 2 cubes

The factorization of a³ + b³ is (a + b)(a² - ab + b²)

∵ The expression is 343x³ + 216y³

∵ \sqrt[3]{343x^{3}} = 7x

∵ \sqrt[3]{216y^{3}} = 6y

∴ The first factor is (7x + 6y)

∵ (7x)² = 49x²

∵ (7x)(6y) = 42xy

∵ (6y)² = 36y²

∴ The second factor is (49x² - 42xy + 36y²)

∴ The factorization of 43x³ + 216y³ is (7x + 6y)(49x² - 42xy + 36y²)

The factorization of the expression of 43x³ + 216y³ is

(7x + 6y)(49x² - 42xy + 36y²)

Learn more:

You can learn more about factors in brainly.com/question/10771256

#LearnwithBrainly

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Step-by-step explanation:

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