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Vikki [24]
2 years ago
15

15. Scott and Tara were asked to find the

Mathematics
1 answer:
Dmitriy789 [7]2 years ago
5 0

Answer:

Both Scott and Tara have responded correctly.

Step-by-step explanation:

we know that

The area of a trapezoid is equal to

A=(1/2)[b1+b2]h

we have

b1=16 cm

b2=24 cm

h=8 cm -----> <em>Note</em> The height is 8 cm instead of 18 cm

substitute

A=(1/2)[16+24](8)

A=160 cm²

<em>Verify Scott 's work</em>

<em>Note</em> Scott wrote A = (1/2)(24 + 16)(8) instead of A = 2(24 + 16)(8)

Remember that the Commutative Property establishes "The order of the addends does not alter its result"

so

(24+16)=(16+24)

A = (1/2)(24 + 16)(8)=160 cm²

<em>Verify Tara's work</em>

<em>Note</em> Tara wrote A = (1/2)(16+24)(8) instead of A = (16 + 24)(8)

A = (1/2)(16+24)(8)=160 cm²

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we have

f(x) = 6x^{2} + 12x -7

To find the zeros equate the function to zero

6x^{2} + 12x -7=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

7= 6x^{2} + 12x

Factor the leading coefficient

7= 6(x^{2} + 2x)

Complete the square. Remember to balance the equation by adding the same constants to each side

7+6= 6(x^{2} + 2x+1)

13= 6(x^{2} + 2x+1)

Rewrite as perfect squares

13= 6(x+1)^{2}

(13/6)=(x+1)^{2}

square root both sides

x+1=(+/-)\sqrt{\frac{13}{6}}

x=-1(+/-)\sqrt{\frac{13}{6}}

x1=-1+\sqrt{\frac{13}{6}}

x2=-1-\sqrt{\frac{13}{6}}

therefore

the answer is

The zeros of the quadratic function are

x=-1+\sqrt{\frac{13}{6}} and x=-1-\sqrt{\frac{13}{6}}


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2 years ago
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A city park commission received a donation of playground equipment from a parents' organization. The area of the playground need
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A machine only accepts 25₵ coins.
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