Question

∆ABC and ∆FDE are congruent by the criterion. (Use the three-letter abbreviation without spaces.)

Answer 1

Answer:

x = 11, y = 8

Step-by-step explanation:

ΔABC and ΔFDE are congruent by the postulate SSS

Equate the congruent sides in the 2 triangles

BC = ED, that is

x + 3 = 14 ( subtract 3 from both sides )

x = 11

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DF = AB, that is

x - y = 3 ← substitute x = 11

11 - y = 3 ( subtract 11 from both sides )

- y = 3 - 11 = - 8 ( multiply both sides by - 1 )

y = 8

Answer 2

Answer:

The value of x is 11 and the value of y is 8.

Step-by-step explanation:

It is given that ∆ABC and ∆FDE are congruent.

The corresponding parts of congruent triangle are congruent.

$AB=FD$                       (CPCTC)

$3=x-y$                 .... (1)

$BC=DE$                       (CPCTC)

$x+3=14$

Subtract 3 from both the sides.

$x=14-3$

$x=11$

The value of x is 11.

Put x=11 in equation (1).

$3=11-y$

Add y on both the sides.

$3+y=11$

Subtract 3 from both the sides.

$y=11-3$

$y=8$

The value of y is 8.