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Sladkaya [172]
2 years ago
7

How many cans of paint are needed to cover an area of 2200 square units if one can of paint covers in area 400 square units

Mathematics
1 answer:
sergij07 [2.7K]2 years ago
5 0

Answer:

6

Step-by-step explanation:

You have a total area of 2,200 sq units to cover... and each can of paint covers 400 sq units.  So, you'll need:

2200 sq units / 400 sq units/can = 5.5 cans

In such problems, we always round up, since you will need 5 full cans of paint, and half of a 6th can.

So, in total you will need 6 cans of paint to cover all 2,200 sq units.

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Answer:

  • See the graph attached
  • x₁ ≈ - 2.1
  • x₂ ≈ 0.2

Explanation:

To solve log (−5.6x + 1.3) = −1 − x graphycally, you must graph this system of equations on the same coordinate plane:

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  • Equatin2:    y = - 1 - x

1) To graph the equation 1 you can use these features of logarithmfunctions:

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  • Range: all real numbers (- ∞ , ∞)

  • x-intercept:

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  • y-intercept:

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  • Pick some other values and build a table:

        x            log (-5.6x + 1.3)

        -1           0.8

        -2           1.1

        -3           1.3

  • You can see such graph on the picture attached: it is the red curve.

2) Graphing the equation 2 is easier because it is a line: y = - 1 - x

  • slope, m = - 1 (the coeficient of x)
  • y - intercept, b = - 1 (the constant term)
  • x - intercept: y = 0 = - 1 - x ⇒ x = - 1
  • The graph is the blue line on the picture.

3) The solution or solutions of the equations are the intersection points of the two graphs. So, now the graph method just requires that you read the x coordinates of the intersection points. From the least to the greatest, rounded to the nearest tenth, they are:

  • <u><em>x₁ ≈ - 2.1</em></u>
  • <u><em>x₂ ≈ 0.2</em></u>

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