Answer:
24 cugini
Step-by-step explanation:
6x2=12
12x2=24
Answer:
The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .
Step-by-step explanation:
Given as :
The mass of liquid water = 50 g
The initial temperature =
= 15°c
The final temperature =
= 100°c
The latent heat of vaporization of water = 2260.0 J/g
Let The amount of heat required to raise temperature = Q Joule
Now, From method
Heat = mass × latent heat × change in temperature
Or, Q = m × s × ΔT
or, Q = m × s × (
-
)
So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )
Or, Q = 50 g × 2260.0 J/g × 85°c
∴ Q = 9,605,000 joule
Or, Q = 9,605 × 10³ joule
Or, Q = 9605 kilo joule
Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer
Answer:
Jean is 9 and Tom is 15.
Step-by-step explanation:
3 years ago, Tom was 12 and Jean was 6, hence Tom was twice as old as Jean.
Since that was their age 3 years ago, they are currently 15 (Tom) and 9 (Jean).
Add 2 years to each of these ages, you get 17 and 11.
17 + 11 = 28
Answer:
Hey there!
1.35 km/s would equal 3020 miles per hour.
Let me know if this helps :)