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kicyunya [14]
2 years ago
6

while watching a football game lin chow decided to list yardage gained as positive integers and yardage lost as negative integer

s after these plays lin recorded 14,-7,and 9 what was the net gain or loss
Mathematics
2 answers:
9966 [12]2 years ago
7 0
<h2>Answer:</h2>

There is a net gain and the net gain is: 16

<h2>Step-by-step explanation:</h2>

<u>Net loss or gain --</u>

If the resultant of the yardage by gaining or losing in the three plays is positive then there is a net gain.

and if the resultant of the yardage by gaining or losing in the three plays is negative then there is a net loss.

The records of the three plays are as follows:

             14 , -7 , and 9 .

By adding up all the entries we have:

14-7+9=16

Since the resultant is positive ( Since,  16>0 )

                  Hence, there is a net gain and the net gain is: 16

Anna007 [38]2 years ago
5 0
All you need to do is add them together. 14+(-7)+9=16
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Answer:

Washing cars= 4 hours

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Step-by-step explanation:

You want to start by creating equations. So one thing we know is that he makes $9 an hour washing cars(x) and $8 walking dogs(y).

$9x+$8y=$116

The second Equation is based off of the hours worked. We know that he worked 6 hours more walking the dogs than he did washing cars, so we can take x(being the washing hours) and add 6 to it to equal y (the number of dog hours).

y=x+6

Now You plug what y equals into the first equation to solve for x.

9x+8(x+6)=116     Next distribute the 8 to each term.

9x+8(x)+8(6)=116

9x+8x+48=116     Add the like terms together (9x+8x)

17x+48=116         Subtract the 48 from both sides

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17x=68             Now divide by 17 on both sides.

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17    17

x=4                 Finally we can take x and plug it back in to one of the equations in order to solve for y. I'm going to choose the second equation.

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To evaluate the effect of a treatment, a sample of n=8 is obtained from a population with a mean of μ=40 , and the treatment is
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Answer:

Step-by-step explanation:

a)

Test statistic:

t=\frac{35-40}{\sqrt{\frac{32}{8} } }

t=-2.5

df=8-1=7

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here test statistic lie in rejection region,that why null hypothesis fails  

so Yes, its significant.

b)

Test statistic:

t=\frac{35-40}{\sqrt{\frac{72}{8} } }

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5 0
1 year ago
A student repeatedly measures the mass of an object using a mechanical balance and gets the following values: 560 g, 562 g, 556
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Step-by-step explanation:

The formula to find the standard deviation:-

\sigma=\sqrt{\dfrac{\sum(x_i-\overline{x})^2}{n}}

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Then,  \overline{x}=\dfrac{\sum_{i=1}^{10} x_i}{n}\\\\\Rightarrow\ \overline{x}=\dfrac{560+562+556+558+560+556+559+561+565+563}{10}\\\\\Rightarrow\ \overline{x}=\dfrac{5600}{10}=560

Now, \sum_{i=1}^{10}(x_i-\overline{x})^2=0^2+2^2+(-4)^2+(-2)^2+0^2+(-4)^2+(-1)^2+1^2+5^2+3^2\\\\\Rightarrow\ \sum_{i=1}^{10}(x_i-\overline{x})^2=76

Then, \sigma=\sqrt{\dfrac{76}{10}}=\sqrt{7.6}=2.76

Hence, the  standard deviation of his measurements = 2.76 g

6 0
2 years ago
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