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2 years ago

The bar graph shows Kieya’s income over a seven-year period. How much more was her income in 2007 than in 2004?

Mathematics

1 answer:

Tpy6a [65]2 years ago

8 0

Answer:

Her income increase by 27.5% from 2004 to 2007

Step-by-step explanation:

Step 1 : Kieya's income in 2004 was $40,000

Step 2 : Kieya's income in 2007 was $51,000

Step 3 : Calculate difference in $

Income in 2007 - Income in 2004 = Increase (+ve) or decrease (-ve) in income

51000 - 40000 = 11000 increase in income

Step 4 : Calculate difference in terms of percentage

<u>Income of 2007-Income of 2004</u> x 100

Income of 2004

<u>51000-40000</u> x 100

40000

= 0.275 x 100

= 27.5 %

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If you are one of the first 100 people to join a new health club, you are charged a joining fee of $49. Otherwise, you are charg

Drupady [299]

Answer:

a) Total cost = 49 + 38.75m

b) Total cost = 149 + 38.75m

c) The graphs of the lines are parallel and both has slope of - 2.5

d)Difference in total cost = $132.5

Step-by-step explanation:

Total cost , TC = Initial membership fee + monthly charges

a) TC = 49 + 38.75m

b)TC = 149 + 38.75m

d) 149 + 38.75(6months) = 381.5

49 + 38.75(12months) = 514

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2 years ago

In 2015, in Buffalo, New York, there were 8,625 arrests, 2,678 robberies, 865 assaults, and 20 murders. The population of Buffal

m_a_m_a [10]

I'm pretty sure simplest form would still be 865:2678
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6 0

2 years ago

Read 2 more answers

Which of the following functions is graphed below?

Butoxors [25]

Answer:

Option (B)

Step-by-step explanation:

Given question is not complete; find the complete question in the attachment.

In the graph attached,

Parent function is an absolute value function,

f(x) = |x|

When this graph is shifted 4 units left, rule for the translation will be,

f(x) → f(x + 4)

Therefore, the new function of above translation will be,

g(x) = f(x + 4) = |x + 4|

Now the graph is shifted 2 units down so the translated function will be,

h(x) = g(x) - 2

h(x) = |x + 4| - 2

If we rewrite the function in the form of an equation, graph will be represented by

⇒ y = |x + 4| - 2

Therefore, Option (B) will be the answer.

8 0

2 years ago

The population can be modeled by P(t) = 82.5 − 67.5cos⎡ ⎣(π/6)t ⎤ ⎦, where t is time in months (t = 0 represents January 1) and

Fed [463]

Answer:

The intervals in which the population is less than 20,000 include

(0 ≤ t < 0.74) and (11.26 < t ≤ 12)

Step-by-step explanation:

P(t) = 82.5 - 67.5 cos [(π/6)t]

where

P = population in thousands.

t = time in months.

During a year, in what intervals is the population less than 20,000?

That is, during (0 ≤ t ≤ 12), when is (P < 20)

82.5 - 67.5 cos [(π/6)t] < 20

- 67.5 cos [(π/6)t] < 20 - 82.5

-67.5 cos [(π/6)t] < -62.5

Dividing both sides by (-67.5) changes the inequality sign

cos [(π/6)t] > (62.5/67.5)

Cos [(π/6)t] > 0.9259

Note: cos 22.2° = 0.9259 = cos (0.1233π) or cos 337.8° = cos (1.8767π) = 0.9259

If cos (0.1233π) = 0.9259

Cos [(π/6)t] > cos (0.1233π)

Since (cos θ) is a decreasing function, as θ increases in the first quadrant

(π/6)t < 0.1233π

(t/6) < 0.1233

t < 6×0.1233

t < 0.74 months

If cos (1.8767π) = 0.9259

Cos [(π/6)t] > cos (1.8767π)

cos θ is an increasing function, as θ increases in the 4th quadrant,

[(π/6)t] > 1.8767π (as long as (π/6)t < 2π, that is t ≤ 12)

(t/6) > 1.8767

t > 6 × 1.8767

t > 11.26

Second interval is 11.26 < t ≤ 12.

Hope this Helps!!!

3 0

2 years ago

Suppose that we want to investigate whether curfews correlate with differences in grades for students in middle school. We selec

Anton [14]

Answer:

Step-by-step explanation:

Hello!

Given the variables

X: Curfew of middle school students (Categorized Yes/No)

Y: Average grade of middle school students. (Categorized: A, B, C, and D)

The objective is to test if there is an association between both variables, you have to conduct a Chi-Square test of independence.

In the null hypothesis, you state that both variables are independent vs. the alternative hypothesis that the variables are dependent.

The hypotheses for this test are:

H₀: Pij= Pi. * P.j i= (1)Yes, (2)No; j= (1)A, (2)B, (3)C, (4)D

H₁: Te variables are not independent.

α: 0.05

$X^2= sum\frac{(O_{ij}-E_{ij})^2}{E_{ij}} ~~X_{(r-1)*(c-1)}$

Where

Oij is the observed frequency for the i-row and j-column

Eij is the expected frequency for the i-row and j-column

r= number of categories in the rows

c= number of categories in the columns

$X^2_{H_0}= 1.4796703$

p-value: 0.687

The p-value is greater than the significance level, so the decision is to not reject the null hypothesis. So using a 5% significance level, you can conclude that having a curfew and the average grades of middle schoolers are two independent variables.

3 0

2 years ago