Ask question

Ask question

All categories

2 years ago

15

Consider a project that has an expected completion time of 60 weeks and a standard deviation of five weeks. What is the probabil

ity that the project will take anywhere between 60 and 65 weeks to complete? (Round to two decimals.)

1 answer:

Nana76 [90]2 years ago

6 0

Answer: 0.3413

Step-by-step explanation:

Given :Mean : $\mu=60\text{ weeks}$

Standard deviation : $\sigma = 5\text{ weeks}$

The formula for z -score :

$z=\dfrac{x-\mu}{\sigma}$

For x= 60 ,

$z=\dfrac{60-60}{5}=0$

For x= 65 ,

$z=\dfrac{65-60}{5}=1$

The p-value = $P(0$

$= 0.8413447-0.5= 0.3413447\approx0.3413$

Hence, the probability that the project will take anywhere between 60 and 65 weeks to complete = 0.3413.

You might be interested in

PLSSS NEED HELP ASAPP :(( ITS MATH

Bezzdna [24]

Answer:

its either 19.25 or 22.75

Step-by-step explanation:

4 0

2 years ago

Find each measure for the given set of data: 11, 13, 17, 20, 22, 25, 27, 31, 31, 33, Mean= Median= Range= interquartile range= I

Tresset [83]

Answer:

Mean=23

Median =23.5

Range=22

Interquartile range = 14

Step-by-step explanation:

Given set of data

11,13,17,20,22,25,27,31,31,33

Mean $=\frac{11+13+17+20+22+25+27+31+31+33}{10}$

$=\frac{230}{10}$

=23

The $(\frac{n}{2})$ th term= the 5th term

=22

The $(\frac{n}{2}+1)^{th}$ term = The $6^{th$ term

= 25

The median = $\frac{22+25}{2}$

=23.5

Range = Highest term - lowest term

=33- 11

=22

Here lower half {11,13,17,20,22}

The middle number of lower half is first quartile.

Q₁ = 17

And lower half is{25,27,31,31,33}

The middle number of upper half is third quartile.

Q₃=31

Interquartile Range =Q₃-Q₁

=31-17

=14

8 0

2 years ago

Zane and Matt are both keen runners. Zane takes 4 minutes to jog around a running track and Matt takes 5 minutes. They start at

Sergio [31]

I believe that the correct answer to this question is B. because matt took more than 5 minutes .

3 0

2 years ago

Marin writes the functions m(x) = StartFraction 3 x Over x + 7 EndFraction and n(x) = StartFraction 7 x Over 3 minus x EndFracti

Svetlanka [38]

Answer:

B.

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

The coordinate values of the vertices of △klm are integers. triangle klm has vertices located at (1, 1), (5, 4) and (5, 1). whic

worty [1.4K]

The rest of the queastion is :
<span> A) (-1, 1), (-1, 4), (2, 1)
B) (0, 0), (3, 4), (0, 5)
C) (-1, 1), (-4, 5), (-1, 5)
D) (0, 0), (-5, 0), (0, 4)
==============================
</span>

<span>The distance between two points (x₁,y₁),(x₂,y₂) = d
$d = \sqrt{ (x2-x1)^{2} + (y2-y1)^{2} }$ </span>

we have <span>K(1, 1), L(5, 4) and M(5, 1)
we will find the length between each two points.
KL = </span><span> $d = \sqrt{ (5-1)^{2} + (4-1)^{2} }$ = 5
</span>LM = <span> $d = \sqrt{ (5-5)^{2} + (1-4)^{2} }$ = 3
KM = </span><span> $d = \sqrt{ (5-1)^{2} + (1-1)^{2} }$ = 4

now check each group from the choices
the group that will give the same result will be the correct choice.
</span>The correct choice is C
<span>C) (-1, 1), (-4, 5), (-1, 5)

check the answer;
</span><span>K'(-1, 1), L'(-4, 5), M'(-1, 5)
</span>
<span>K'L' = <span> $d = \sqrt{ (-4+1)^{2} + (5-1)^{2} }$ = 5
</span>L'M' = <span> $d = \sqrt{ (-1+4)^{2} + (5-5)^{2} }$ = 3
K'M' = </span><span> $d = \sqrt{ (-1+1)^{2} + (5-1)^{2} }$ = 4</span></span>

6 0

2 years ago