Question

This is a cross-sectional view of candy bar ABC. A candy company wants to create a cylindrical container for candy bar ABC so that it is circumscribed about the candy bar. If segment AD = 3 cm, what is the smallest diameter of wrapper that will fit the candy bar?
a.3
b.4
c.5
d.6

Answer 1

Answer:

d. 6cm

Step-by-step explanation:

All of the shapes together make a right triangle.

When a right triangle is circumscribed in a circle, the diameter IS the hypotenuse.

to find the diameter, look at the hypotenuse which is line AC.

Half of AC is AD and DC which are equal. we know this because the single and double hash marks on the shapes show that pretty much all the sides are equal. point E is exactly in the middle, I can tell because AE and EB are congruent, and point F is also a bisector b/c BF and FC both are equal. From there we can figure out that AD and DC are equal. AD is equal to 3cm and since AD also equals DC, DC equals 3cm. add them together and AC (AKA the hypotenuse is 6).

Hypotenuse in a right triangle is the diameter to a circle and therefore the smallest diameter of wrapper that will fit the candy bar is 6cm.