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2 years ago

here is the histogram of a data distribution. which of the following numbers is closest to the mean of this distribution

Mathematics

2 answers:

lbvjy [14]2 years ago

5 0

Answer:

Option (D)

Step-by-step explanation:

Mean= $\frac{Sum of observations}{Number of observations}$

here, observations are

1×1=1

2×2=2

3×3=9

4×1=4

5×1=5

6×2=12

7×3=21

8×1=8

9×1=9

10×0=0

hence, sum of observations =1+4+9+4+5+12+21+8+9+0=73

Number of observations are=1+2+3+1+1+2+3+1+1+0=15

Mean= $\frac{73}{15}$

Mean=4.8..

nearest to 5 .

Hence, option (D) is correct.

gogolik [260]2 years ago

4 0

Answer:

Step-by-step explanation:

1+2+2+3+3+3+4+5+6+6+7+7+7+8+9=73

73/15≈5

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Answer:

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Step-by-step explanation:

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Marina86 [1]

Answer:

$\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2})$

And when we apply the limit we got that:

$\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2}) =1$

Step-by-step explanation:

Assuming this complete problem: "The following formula for the sum of the cubes of the first n integers is proved in Appendix E. Use it to evaluate the limit . 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2"

We have the following formula in order to find the sum of cubes:

$\lim_{n\to\infty} \sum_{n=1}^{\infty} i^3$

We can express this formula like this:

$\lim_{n\to\infty} \sum_{n=1}^{\infty}i^3 =\lim_{n\to\infty} [\frac{n(n+1)}{2}]^2$

And using this property we need to proof that: 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2

$\lim_{n\to\infty} [\frac{n(n+1)}{2}]^2$

If we operate and we take out the 1/4 as a factor we got this:

$\lim_{n\to\infty} \frac{n^2(n+1)^2}{n^4}$

We can cancel $n^2$ and we got

$\lim_{n\to\infty} \frac{(n+1)^2}{n^2}$

We can reorder the terms like this:

$\lim_{n\to\infty} (\frac{n+1}{n})^2$

We can do some algebra and we got:

$\lim_{n\to\infty} (1+\frac{1}{n})^2$

We can solve the square and we got:

$\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2})$

And when we apply the limit we got that:

$\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2}) =1$

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2 years ago

Two cards are drawn at random with replacement. Find P(not blue, then pink). (Remember, percent is a fraction with 100 in the de

Nuetrik [128]

<h3>Answer: 32%</h3>

=======================================

Explanation:

There are 10 cards total. Of which, 8 are not blue. You can think of it as "there are 2 blue, so 10-2 = 8 are not blue", or you can count out the non-blue cards. The first option is faster in my opinion.

The probability of not getting blue is 8/10 = 0.80

After picking a first card and then putting it back, we will still have 10 cards. There are 4 pink cards out of this total, so 4/10 = 0.40 is the probability of getting a pink card.

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Multiply the two values we found earlier

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