Answer:
Explanation:
1) Effect on R-type instructions:
log2(128) = 7 [since 128=27]
opcode = 6
rs = 7
rt = 7
rd = 7
shamt = 5
funct = 6
Here all the bits ends up with 2 additional bits. As there are 6 bits for opcode in R-type instruction the size of word is 44.
.2) Effect on I-type Instruction:
log2(128) = 7 [since 128=27]
opcode = 6
rs = 7
rt = 7
immediate = 16
The word size of the I-type instruction is also 44.
3)
The programs will take long time to do the operations if the instruction encoding is long.
It means the format must be larger as the increases are not aligned.
The code will decrease if there are more registers.
Because more registers can hold more information without going to memory.
As this leads to fewer calls to load or store the code will decrease.
Answer:
MAR bit
Explanation:
The MPC computers area set of software and hardware standards that was developed by the consortium of computer firms which is led by Microsoft. It contains the address of a next microcode for the Mic1 emulator foe execution.
The part of the executing microcode instruction that determines the value which is placed in the MOC is the MAR bit. The MAR is the memory address register in the CPU which stores the memory address or such addresses to which some data will be sent and also stored.
Answer:
The true statements are :
A. assertEquals(student1,student2)
C. assertSame(student1,student3)
Explanation:
AssertEquals() asserts that the objects are equal, but assertSame() asserts that the passed two objects refer to the same object or not, if found same they return true, else return false.
Answer:
High level Language
understand
Explanation:
rocket is 0...4433456u888
