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2 years ago

6

The intensity of solar radiation near the earth is 1.4 × 103 W/m2 . What force is exerted by solar radiation impinging normally

on a 5.0 m2 perfectly reflecting panel of an artificial satellite orbiting the earth?

1 answer:

jeka942 years ago

5 0

Answer:

4.665×10⁻¹¹ N

Explanation:

Intensity of solar radiation=I=1.4×10³ W/m²

Area of panel=A=5.0 m²

speed of sound=c=3×10⁸ m/s

$P_t=\text {Total\ Solar\ Radiation\ Pressure}$

$P_t=2\frac{I}{c}\\\Rightarrow P_t=2\frac{1.4\times 10^{-3}}{3\times 10^{8}}\\\Rightarrow P_t=0.933\times 10^{-11}$

∴Total Solar Radiation Pressure=0.933×10⁻¹¹ Ws/m³

Force= Pressure×Area

Force=0.933×10⁻¹¹×5

Force=4.665×10⁻¹¹ Ws/m=4.665×10⁻¹¹ N

∴Force is exerted by solar radiation impinging normally on a perfectly reflecting panel of an artificial satellite orbiting the earth is 4.665×10⁻¹¹ N

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