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1 year ago

A man on a diet is losing four-tenths of a kilogram each day. How many days will it take him to lose 3.2 kilograms?

Mathematics

1 answer:

Alborosie1 year ago

3 0

so he's losing 4/10 of a Kg daily, how many times will that equal 3.2 Kgs? namely how many times does 4/10 go into 3.2?

well, let's firstly convert 3.2 to a fraction, and then divide.

$\bf \stackrel{\textit{1 decimal}}{3.\underline{2}}\implies \cfrac{32}{\underset{\textit{1 zero}}{1\underline{0}}}\implies \cfrac{16}{5} \\\\[-0.35em] ~\dotfill$

$\bf \cfrac{16}{5}\div \cfrac{4}{10}\implies \cfrac{16}{5}\div \cfrac{2}{5}\implies \cfrac{\stackrel{8}{~~\begin{matrix} 16 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}{~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\cdot \cfrac{~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies 8$

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1 year ago

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2 years ago

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Answer:

The confidence interval for the difference in proportions is

$-0.028\leq p_1-p_2 \leq 0.096$

No. As the 95% CI include both negative and positive values, no proportion is significantly different from the other to conclude there is a difference between them.

Step-by-step explanation:

We have to construct a confidence interval for the difference of proportions.

The difference in the sample proportions is:

$p_1-p_2=x_1/n_1-x_2/n_2=(183/217)-(322/398)=0.843-0.809\\\\p_1-p_2=0.034$

The estimated standard error is:

$\sigma_{p_1-p_2}=\sqrt{\frac{p_1(1-p_1)}{n_1}+\frac{p_2(1-p_2)}{n_2} } \\\\\sigma_{p_1-p_2}=\sqrt{\frac{0.843*0.157}{217}+\frac{0.809*0.191}{398} } \\\\\sigma_{p_1-p_2}=\sqrt{0.000609912+0.000388239}=\sqrt{0.000998151} \\\\ \sigma_{p_1-p_2}=0.0316$

The z-value for a 95% confidence interval is z=1.96.

Then, the lower and upper bounds are:

$LL=(p_1-p_2)-z*\sigma_p=0.034-1.96*0.0316=0.034-0.062=-0.028\\\\\\UL=(p_1-p_2)+z*\sigma_p=0.034+1.96*0.0316=0.034+0.062=0.096$

The confidence interval for the difference in proportions is

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1 year ago

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1 year ago

The state of Wisconsin would like to understand the fraction of its adult residents that consumed alcohol in the last year, spec

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Answer:

The answer is below

Step-by-step explanation:

What we should do is the following:

First, from the random sample of 852 researchers, it is necessary to obtain the number of adult residents who consumed alcohol in the past year.

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After this, we must compare if the proportion is exactly 70% or different from it.

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Alternative hypothesis: The proportion of adult residents who consumed alcohol in the last year in the state of Wisconsin is not equal to 70%

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1 year ago