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andrew-mc [135]
2 years ago
14

Mama's Italian Restaurant has collected data about customer sauce orders. It calculated that P(marinara) = 0.82, P(alfredo) = 0.

76, and P(marinara or alfredo) = 0.96. Determine the P(marinara and alfredo).
Mathematics
1 answer:
Keith_Richards [23]2 years ago
7 0
P ( m ) = 0.82
P ( a ) = 0.76
P ( m or a ) = 0.96
P ( m and a ) = ?
--------------------------
P ( m or a ) = P ( m ) + P ( a ) - P ( m and a )
P ( m and a ) = P ( m ) + P ( a ) - P ( m or a ) =
= 0.82 + 0.76 - 0.96 = 0.62
Answer: P ( marinara and alfredo ) = 0.62
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227 - 19.76 t = 1,052 - 92.57 t
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2 years ago
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The commission earned on the sale of a car can be represented by the equation c(p)=250+0.02p where c represents the commission a
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Answer:

1) His total commission is $1,234.3

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Step-by-step explanation:

1) 21640*0.02= 432.8+ 250= 682.8

15075*0.02= 301.5+ 250= 551.5

682.8+ 551.5= 1,234.3

2) 745.8- 250= 495.8/ 0.02= 24,790

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2 years ago
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Suppose that you want to estimate the mean pH of rainfalls in an area that suffers from heavy pollution due to the discharge of
labwork [276]

Answer:

The  number of rainfalls is n  =96

The answer to the second question is  no it will not be valid this because from the question we are told that the experiment require one pH reading per rainfall so getting multiply specimens(used for the  pH reading) from  one rainfall will make the experiment invalid.

Step-by-step explanation:

from the question we are told that

    The  standard deviation is  \sigma  =  0.5

     The  margin of error is  E  =  0.1

Given that the confidence level is  95%  then we can evaluate the level of significance as

                  \alpha  =  100 -  95

                  \alpha  =  5 \%

                 \alpha  =0.05

Next we will obtain the critical value of \frac{\alpha }{2} from the normal distribution table , the value is  Z_{\frac{\alpha }{2} } =  1.96

Generally the sample size is mathematically represented as

           n  =  [\frac{Z_{\frac{\alpha }{2} *  \sigma }}{ E} ]^2

substituting values

             n  =  [\frac{1.96 * 0.5 }{ 0.1} ]^2

            n  =96

The answer to the second question is  no the validity is null this because from the question we are told that the experiment require  one pH reading per rainfall so getting multiply specimens(used for the  pH reading) from  one rainfall will make the experiment invalid

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2 years ago
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Answer / Step-by-step explanation:

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Random: This refers to an unpredictable pattern of arrangement.  Without a specific aim or logical procedural pattern.

Uniform Probability distribution: This is a type of probability distribution in which the outcomes of distribution irrespective of the pattern or distance results in equally likely outcomes.

Uniform distribution is one of the widely used distributions although it's one of the simplest ones. The idea behind this distribution is that, unlike the other distributions, the likelihood of the any outcome in the distribution range is the same.

Now that we have a brief knowledge of the key terms within the question, hence, to start answering the question,

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We have: P = 1 - 1/3 . 1/3

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(c) This is basically impossible as the area of a dot is negligible.

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Therefore: P = 1 - 1 /3

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