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igor_vitrenko [27]
2 years ago
3

What is divide 4860 in the ratio 5:4:3 please help

Mathematics
1 answer:
Finger [1]2 years ago
7 0
If it is 5 : 4 : 3, total portions are 12
one portion is,
4860 / 12
405

So
5 : 4 : 3
5*405 : 4*405 : 3*405
2025 : 1620 : 1212


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Find the sum (3.2+4x)+(18.25+6x)=
tatiyna

Answer:    -2.145

Step-by-step explanation:

(3.2+4x)+(18.25+6x)=

Simplifying

(3.2 + 4x) + (18.25 + 6x) = 0

Remove parenthesis around (3.2 + 4x)

3.2 + 4x + (18.25 + 6x) = 0

Remove parenthesis around (18.25 + 6x)

3.2 + 4x + 18.25 + 6x = 0

Reorder the terms:

3.2 + 18.25 + 4x + 6x = 0

Combine like terms: 3.2 + 18.25 = 21.45

21.45 + 4x + 6x = 0

Combine like terms: 4x + 6x = 10x

21.45 + 10x = 0

Solving

21.45 + 10x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-21.45' to each side of the equation.

21.45 + -21.45 + 10x = 0 + -21.45

Combine like terms: 21.45 + -21.45 = 0

0 + 10x = 0 + -21.45

10x = 0 + -21.45

Combine like terms: 0 + -21.45 = -21.45

10x = -21.45

Divide each side by '10'.

x = -2.145

Simplifying

x = -2.145

8 0
2 years ago
Read 2 more answers
How to round 47,125 to the nearest ten,to the nearest hundred, to the nearest thousand and to the nearest ten thousand
Tasya [4]
To be able to round the number 47,125 to the nearest tenth, hundredth, and thousandth place you need to know were those places are. The tens place is the second one from the right hand side. The hundreds place is the third one from the right hand side and the thousands place is the one right after the comma. Now, to round to the tens place, you need to look at the place right behind it (which would be the ones place) then you need to analyze. If the number in the ones place is between 0-4 you can NOT round the tens place but, if it is between 5-9 you can. The same rule applies when you round to the hundreds and thousands place. So the number you should end up with is - 47,135. 
8 0
2 years ago
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Doris ran 2.5 kilometers, then sprinted 300 meters and finally walked 1 4 of the distance she sprinted. How many meters did she
mr Goodwill [35]

Answer:

She traveled a total of 2875 metres during practice.

Step-by-step explanation:

Doris ran 2.5 kilometres, then sprinted 300 meters and finally walked 1/4 of the distance she sprinted.

To find the total distance that she traveled, we simply add the distance that she ran, sprinted and walked.

We will convert all distances to metres.

She ran 2.5 kilometres:

1 km = 1000 m

2.5 km = 2.5 * 1000 = 2500 m

So, she ran 2500 m.

She sprinted 300 m.

Se walked 1/4 the distance that she sprinted:

1/4 * 300 = 75 m

She walked 75 m.

Therefore, the total distance she traveled is:

2500 + 300 + 75 = 2875 m

She traveled a total of 2875 metres during practice.

5 0
2 years ago
On a coordinate plane, 2 polygons are shown. Polygon A B C D has points (1, negative 6), (5, negative 6), (6, negative 2), and (
irga5000 [103]

Answer:

The correct option is;

Use a scale factor of 2

Step-by-step explanation:

The parameters given are;

A = (1, -6)

B = (5, -6)

C = (6, -2)

D = (0, -2)

A'' = (1.5, 4)

B'' = (3.5, 4)

C'' = (4, 2)

D'' = ( 1, 2)

We note that the length of side AB in polygon ABCD = √((5 -1)² + (-6 - (-6))²) = 4

The length of side A''B'' in polygon A''B''C''D'' = √((3.5 -1.5)² + (4 - 4)²) = 2

Which gives;

AB/A''B'' = 4/2 = 2

Similarly;

The length of side BC in polygon ABCD = √((6 -5)² + (-2 - (-6))²) = √17

The length of side B''C'' in polygon A''B''C''D'' = √((4 -3.5)² + (2 - 4)²) = (√17)/2

Also we have;

The length of side CD in polygon ABCD = √((6 -0)² + (-2 - (-2))²) = 6

The length of side C''D'' in polygon A''B''C''D'' = √((4 -1)² + (2 - 2)²) = 3

For the side DA  and D''A'', we have;

The length of side DA in polygon ABCD = √((1 -0)² + (-6 - (-2))²) = √17

The length of side D''A'' in polygon A''B''C''D'' = √((1.5 -1)² + (4 - 2)²) = (√17)/2

Therefore the Polygon A B C D can be obtained from polygon A''B''C''D'' by multiplying each side of polygon A''B''C''D'' by 2

The correct option is therefore;

Use a scale factor of 2.

3 0
2 years ago
Read 2 more answers
The average sea level in 1900 at London bridge was 33 feet. In 1990 it was 33.08 feet. Use linear interpolation or extrapolation
eduard

Answer:

In 1956, the height will be 33.05 ft

Step-by-step explanation:

Let +x+ = number of years after 1900

Calll 1900 +x+=+0+

Then 1990 is +x+=+90+

Let +y+ = height in feet

--------------------------

You are gven the points

( 0, 33 )

( 90, 33.08 )

Use general point-slope formula

+%28+y+-+33+%29+%2F+%28+x+-+0+%29+=+%28+33.08+-+33+%29+%2F+%28+90+-+0+%29+

Multiply both sides by +90x+

+90%2A%28+y+-+33+%29+=+.08x+

+90y+-+2970+=+.08x+

+90y+=+.08x+%2B+2970+

+y+=+.000889x+%2B+33+ ( equation to use )

--------------------------

Check:

does it go through ( 90, 33.08 ) ?

+33.08+=+.000889%2A90+%2B+33+

+33.08+=+.08001+%2B+33+

+33.08+=+33.08001+

close enough

-------------------------------

(a)

+x+=+61%0D%0A%7B%7B%7B+y+=+.000889x+%2B+33+

+y+=+.000889%2A61+%2B+33+

+y+=+.0542+%2B+33+

+y+=+33.0542+

In 1961, the height will be 33.05 ft

8 0
2 years ago
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