Let m∠CLN = x. Then m∠ALM = 3x, and m∠A = 90°-x, m∠C = 90°-3x.
The sum of angles of ∆ABC is 180°, so we have
... 180° = 40° + m∠A + m∠C
Using the above expressions for m∠A and m∠C, we can write ...
... 180° = 40° + (90° -x) + (90° -3x)
... 4x = 40° . . . . . . . . . add 4x-180°
... x = 10°
From which we conclude ...
... m∠C = 90°-3x = 90° - 3·10° = 60°
The ratio of CN to CL is
... CN/CL = cos(∠C) = cos(60°)
... CN/CL = 1/2
so ...
... CN = (1/2)CL
Answer:
v(m) = 8 + 48m+ 180m² +216m³
Step-by-step explanation:
Let's first of all represent the edge of the the cube as a function of minutes.
Initially the egde= 2feet
As times elapsed , it increases at the rate of 6 feet per min, that is, for every minute ,there is a 6 feet increase.
Let the the egde be x
X = 2 + 6(m)
Where m represent the minutes elapsed.
So we Al know that the volume of an edge = edge³
but egde = x
V(m) = x³
but x= 2+6(m)
V(m) = (2+6m)³
v(m) = 8 + 48m+ 180m² +216m³
Xy = -109i
We could find the value of i by substitute the algebraic form of x and y to the equation above
xy = -109i
(10 - 3i)(3 - 10i) = -109i
(10)(3) -3i(3) + 10(-10i) - 3i(-10i) = -109i
30 - 9i - 100i -30i² = -109i
multiply both side by -1
-30 + 9i + 100i + 30i² = 109i
30i² + 9i + 100i - 109i - 30 = 0
30i² - 30 = 0
30i² = 30
i² = 1
i = -1 or i = 1
Then find the value of x and y if i = -1
If i = -1, therefore
x = 10 - 3(-1)
x = 10 + 3
x = 13
y = (3 - 10i)
y = 3 - 10(-1)
y = 3 + 10
y = 13
x/y = 13/13 = 1
Then find the value of x and y if i = 1
x = 10 - 3(1)
x = 10 - 3
x = 7
y = (3 - 10i)
y = 3 - 10(1)
y = 3 - 10
y = -7
x/y = 7/-7 = -1
The value of x/y is either 1 or -1
40+1=41
10×4+1=41
that is what I have so there you go
Answer: 1 / 27
Step-by-step explanation: p (B1) = 1 / 3
p (B2) = 1 / 3
p (B3) = 1 / 3
pro (B1 X B2 X B3) = 1 / 3 X 1 / 3 X 1 / 3 = 1 / 27
