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Yanka [14]
2 years ago
9

Which statement about –2h2 – 15h – 7 is true? One of the factors is (h + 2). One of the factors is (3h – 2). One of the factors

is (2h + 1). One of the factors is (h – 7).
Mathematics
2 answers:
Stels [109]2 years ago
8 0

Answer:

One of the factors is (2h + 1).

Step-by-step explanation:

Given equation,

-2h^2 - 15h - 7

-(2h^2+15h+7)

By middle term splitting,

-(2h^2+(14+1)h+7)

-(2h^2+14h+h+7)

-(2h(h+7)+1(h+7))

-(2h+1)(h+7)

\implies -2h^2 - 15h - 7=-(2h+1)(h+7)

Thus the true statement is,

One of the factors of the given expression is (2h + 1).

romanna [79]2 years ago
7 0

Answer:

  One of the factors is (2h + 1)

Step-by-step explanation:

The expression factors as ...

  -(h +7)(2h +1)

One of the factors is (2h + 1).

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 By properties of powers, if you have the same base, you can substract the exponents. Then:

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Mason owns a trucking company. For every truck that goes out, Mason must pay the driver $13 per hour of driving and also has an
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Answer: The required system of equations are

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Step-by-step explanation:

Let x represent the number of hours

that the driver worked.

Let y represent the number of miles that the truck drove.

For every truck that goes out, Mason must pay the driver $13 per hour of driving and also has an expense of $1 per mile driven for gas and maintenance. If on a particular day, his total expenses for the driver, gas and truck maintenance were $258, it means that

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A contractor has submitted bids on three state jobs: an office building, a theater, and a parking garage. State rules do not all
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Answer:

The following are the answer to this question:

Step-by-step explanation:

In the given question the numeric value is missing which is defined in the attached file please fine it.  

Calculating the probability of the distribution for x:

\to f(x) = 0.19\  for \ x=14\\\\\to  f(x) = 0.29 \ for\ x=7\\\\\to f(x) = 0.38\  for \ x=1\\\\\to f(x)=0.14 \ for \ x=0\\

The formula for calculating the mean value:

\bold{ E(X)= x \times f(x)}

          =14 \times 0.19+7 \times 0.29+1 \times 0.38+0\times 0.14\\\\=2.66 + 2.03+0.38+ 0\\\\=5.07

\bold{E(X^2) = x^2 \times f(x)}

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use formula for calculating the Variance:

\to \bold{\text{Variance}= E(X^2) -[E(X)]^2}

                  = 51.83 - (5.07)^2\\\\= 51.83 -  25.70\\\\=26.13

calculating the value of standard deivation:

Standard Deivation (SD) = \sqrt{Variance}

                                          = \sqrt{26.13} \\\\=5.111

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