Answer: y=9 (point B on the graph)
Step-by-step explanation:
y=3x
x=3
y=3(3) (3×3)
3x3=9
So 9(y)=3(3x)
Point B which is located at the 9 mark
So the given series is "16, 06, 68, 88, __"
Count all the cyclical opening in each of these numbers. For example in 16, there is a one cyclical loop present in it(the one in 6), similarly in 06 it is two(one in zero and one in 6), going ahead, in 68 it is 3(one in 6 and two in 8).
From here on things become simple: hence, the cyclical figures in these equations written down becomes 1,2,3,4,_,3.
Let's now try solving the above sequence, going by the logical reasoning the only number that can fill in the gap should be 4.
The second question:
Consider the division expression
. Select all multiplication equations that correspond to this division expression.


Answer:
1. See Explanation
2.
and 
Step-by-step explanation:
Solving (a):
Given


Required
Interpret
in 2 ways
<u>Interpretation 1:</u> Number of groups if there are 5 students in each
<u>Interpretation 2:</u> Number of students in each group if there are 5 groups
<u>Solving the quotient</u>


<u>For Interpretation 1:</u>
The quotient means: 12 groups
<u>For Interpretation 2:</u>
The quotient means: 12 students
Solving (b):
Given

Required
Select all equivalent multiplication equations
Let ? be the quotient of t 
So, we have:

Multiply through by 2


Rewrite as:
--- This is 1 equivalent expression
Apply commutative law of addition:
--- This is another equivalent expression