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1 year ago

10

A machine can stamp 40 envelopes in 8 mins. How many of these machines working simultaneously are required or needed to stamp 12

0 envelopes per minutes.

2 answers:

zzz [600]1 year ago

8 0

Answer: The required number of machines is 24.

Step-by-step explanation: Given that a machine can stamp 40 envelopes in 8 mins.

We are to find the number of machines that are working simultaneously are required or needed to stamp 120 envelopes per minutes.

We will be using the UNITARY method to solve the given problem.

In 8 minutes, number of envelopes stamped by a machine = 40.

So, in 1 minute, the number of envelopes stamped by the machine is given by

$\dfrac{40}{8}=5.$

Now, number of machines required to stamp 5 envelopes in 1 minute = 1.

So, number of machines required to stamp 1 envelope in 1 minute is

$\dfrac{1}{5}.$

Therefore, the number of machines required to stamp 120 envelopes in 1 minute is given by

$\dfrac{1}{5}\times120=24.$

Thus, the required number of machines is 24.

kati45 [8]1 year ago

3 0

Answer:

24 minutes

Step-by-step explanation:

let y be the 120 envelope per minutes.

40/8 = 120/y

40y= 8 x 120

40x =960

x = 960/40

= 24 minutes

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Using the quadratic formula to solve 5x = 6x2 – 3, what are the values of x?

Tema [17]

Your x values are 1.24 and -0.404.
First you need to make the equation equal 0, and you can do this simply by subtracting 5x, so you get
6x² - 3 - 5x = 0
The quadratic formula is (-b +- √b² - 4ac)/2a, where a is the x², b is the x, and c is the value. This means we can just substitute it in.
You find the value of the part inside the square root, which is -5² - 4 × 6 × -3 = 97. Now we can use this to substitute in to (5 +- √97)/12. We can do it with the plus sign, and get 1.24, and then with the subtract sign and get -0.404.

I hope this helps!

4 0

2 years ago

Eliza started her savings account with $100. Each month she deposits $25 into her account. Determine the average rate of change

Afina-wow [57]

First, lets create a equation for our situation. Let $x$ be the months. We know four our problem that <span>Eliza started her savings account with $100, and each month she deposits $25 into her account. We can use that information to create a model as follows:
</span> $f(x)=25x+100$
<span>
We want to find the average value of that function </span>from the 2nd month to the 10th month, so its average value in the interval [2,10]. Remember that the formula for finding the average of a function over an interval is: $\frac{f(x_{2})-f(x_{1})}{x_{2}-x_{1} }$ . So lets replace the values in our formula to find the average of our function:
$\frac{25(10)+100-[25(2)+100]}{10-2}$
$\frac{350-150}{8}$
$\frac{200}{8}$
$25$

We can conclude that <span>the average rate of change in Eliza's account from the 2nd month to the 10th month is $25.</span>

6 0

2 years ago

Last year, 46% of business owners gave a holiday gift to their employees. A survey of business owners indicated that 35% plan to

DiKsa [7]

Answer:

a) Number = 60 *0.35=21

b) Since is a left tailed test the p value would be:

$p_v =P(Z$

c) If we compare the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% the proportion of business owners providing holiday gifts had decreased from the 2008 level.

We can use as smallest significance level 0.044 and we got the same conclusion.

Step-by-step explanation:

Data given and notation

n=60 represent the random sample taken

X represent the business owners plan to provide a holiday gift to their employees

$\hat p=0.35$ estimated proportion of business owners plan to provide a holiday gift to their employees

$p_o=0.46$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Part a

On this case w ejust need to multiply the value of th sample size by the proportion given like this:

Number = 60 *0.35=21

2) Part b

We need to conduct a hypothesis in order to test the claim that the proportion of business owners providing holiday gifts had decreased from the 2008 level:

Null hypothesis: $p\geq 0.46$

Alternative hypothesis: $p < 0.46$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.35 -0.46}{\sqrt{\frac{0.46(1-0.46)}{60}}}=-1.710$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(Z$

Part c

If we compare the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% the proportion of business owners providing holiday gifts had decreased from the 2008 level.

We can use as smallest significance level 0.044 and we got the same conclusion.

8 0

2 years ago

3 Explain how the distributive property helps us multiply the following polynomials and why and how the final products differ: ●

Pavel [41]

<span>●(a + b)^2 = (a +b) (a +b)

(a + b) (a + b) = a*a + a*b + b*a+ b*b = a^2 + 2ab + b^2

●(a – b)^2 (a - b) (a -b)

(a - b) (a -b) = a*a + -ab - ba + b*b = a^2 - 2ab + b^2

●(a - b)(a + b). =

= (a - b) (a + b) = a*a + ab - ba - b*b = a^2 - b^2
</span>

4 0

2 years ago

19% of a certain population of students at Hardy-Weinberg equilibrium is affected by an autosomal dominant condition called ‘laz

bazaltina [42]

Answer:

81%

Step-by-step explanation:

Let 'L' be the dominant and 'l' e the recessive allele for ‘lazybuttness’.

Since ‘lazybuttness’ is an autosomal dominant condition, the 19% of students affected by the condition correspond to the homozygous dominant (LL) and heterozygous (Ll) genotypes. Therefore, the rest of the population has the homozygous recessive genotype (ll) and is not affected. The frequency of students not affected is:

F = 100% - 19% = 81%

3 0

2 years ago