Question

What is the solution of this system of linear equations? 3y = 3 y equals StartFraction 3 over 2 EndFraction x plus 6.x + 6 y – StartFraction one-half EndFraction y minus StartFraction 1 over 4 EndFraction x equals 3.x = 3 (3, 6) (2, 1) no solution infinite number of solutions

Answer 1

Answer:

No Solution

Step-by-step explanation:

The given set of equations is:

$3y=\frac{3}{2}x+6\\\\ \frac{1}{2}y-\frac{1}{4}x=3$

Dividing first equation by 3, we get:

$y=\frac{1}{2}x+2$

Substituting this value of y in second equation, we get:

$\frac{1}{2}(\frac{1}{2}x+2)-\frac{1}{4}x=3\\\\ \frac{1}{4}x+1-\frac{1}{4}x=3\\\\ 1=3$

Which is not true.

Thus, substituting one equation into another result into a False result, from here we can conclude that the given system of equations has No Solution and this is because two lines are parallel and they will never meet at any point.

Answer 2

Answer:

c

Step-by-step explanation:

Answer 3

first one, No solution