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jek_recluse [69]
2 years ago
11

Timothy wants to estimate the mean number of siblings for each student in his school. He records the number of siblings for each

of 75 randomly selected students in the school. What is the statistic?
(A) the specific number of siblings for each randomly selected student
(B) the 75 randomly selected students
(C) the mean number of siblings for the randomly selected students
(D) the mean number of siblings for all students in the school
(E) all the students in the school
Mathematics
1 answer:
Ede4ka [16]2 years ago
4 0

Answer:

(A) the specific number of siblings for each randomly selected student

Step-by-step explanation:

First Timothy wants to estimate the mean number of siblings for each student in his school

So he selected a random sample of 75 students, then recorded the number of siblings they have

He later find the mean.

You can see the mean was obtained from the selected group not all students in the school hence option D and E are not correct.

Option A clearly indicates a mean was obtained for the siblings that were from the randomly selected students.

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What is the future value of $845 a year for seven years at an interest rate of 11.3 percent? $6,683.95 $6,075.69 $8,343.51 $8,00
k0ka [10]
The future value of cash whose initial value is $845, at the rate of 11.3% for 7 years will be calculated using the compound interest rate, that is:
A=p(1+r/100)^n
where:
A=future amount
r=rate=11.3%=0.113
time=7 years
thus the future value of our cash will be:
A=845(1+0.113)^7
A=845(1.113)^7
A=$1,787.82 
7 0
2 years ago
Read 2 more answers
Describe how you regroup when you find the sum of 64 + 43
vaieri [72.5K]
When you regroup you are basically breaking down the problem.
You would do 60 + 40=?
Then you would do 4 + 3= ?
Your answer would come out to 107
4 0
2 years ago
What two products would you add to find 713​x48
umka21 [38]

9514 1404 393

Answer:

  40·713 and 8·713

Step-by-step explanation:

When this multiplication is carried out "by hand", the usual sum of partial products is ...

  8·713 + 40·713

5 0
2 years ago
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A box of buttons contains the same number of each type of button. It contains 220g of buttons
ra1l [238]

Answer:

a) 18 button a buttons are required to fill the bag.

b) 12 button b buttons are required to fill the bag.

c) There are 11 buttons of each type in the box containing 220 g of buttons.

Step-by-step explanation:

Complete Question

Two button types, button a weighing 8 grams and button b weighing 12 grams. The buttons are sold in bags. Each bag contains 144 grams of buttons.

a) How many of button a are needed to fill one bag?

b) How many of button b are needed to fill one bag?

c) A box of buttons contains the same number of each type of button it contains 220g of buttons. How many of each type of button are in the box.

Solution

a) A bag contains 144 grams of buttons.

Button a weighs 8 grams per button.

Total number of button a buttons required to fill up the bag = (144/8) = 18 button a buttons.

b) A bag contains 144 grams of buttons.

Button b weighs 12 grams per button.

Total number of button b buttons required to fill up the bag = (144/12) = 12 button a buttons.

c) A box of buttons weighing 220 g contains the same number of each type of button.

Let this number be n.

This means the Total weight of button a buttons in this box = 8n

total weight of button b buttons in this box = 12n

Sum total of the weight of the buttons = 8n + 12n = 20n

20n = 220

n = (220/20) = 11.

This means there are 11 buttons of each type in the box containing 220 g of buttons.

Hope this Helps!!!

6 0
2 years ago
Which of the following events are equal? (a) A = {1,3}; (b) B = {x | x is a number on a die }; (c) C = {x | x2 −4x +3=0 }; (d) D
rosijanka [135]

Answer:

A and C

Step-by-step explanation:

To determine which events are equal, we explicitly define the elements in each set builder.

For event A

A={1.3}

for event B

B={x|x is a number on a die}

The possible numbers on a die are 1,2,3,4,5 and 6. Hence event B is computed as

B={1,2,3,4,5,6}

for event C

C=[x|x^{2}-4x+3]\\solving  x^{2}-4x+3\\x^{2}-4x+3=0\\x^{2}-3x-x+3=0\\x(x-3)-1(x-3)=0\\x=3 or x=1

Hence the set c is C={1,3}

and for the set D {x| x is the number of heads when six coins re tossed }

In the tossing a six coins it is possible not to have any head and it is possible to have head ranging from 1 to 6

Hence the set D can be expressed as

D={0,1,2,3,4,5,6}

In conclusion, when all the set are compared only set A and set C are equal

5 0
2 years ago
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