Question

The following reaction proceeds at a rate such that 3 mole of A is consumed per minute. Given this, how many moles of C are produced per minute? 2A+2B→4C Express your answer with the appropriate units.

Answer 1

Answer:

6 moles of C are produced per minute

Explanation:

According to law of mass action for the given reaction-

Rate = $-\frac{1}{2}\frac{\Delta [A]}{\Delta t}=-\frac{1}{2}\frac{\Delta [B]}{\Delta t}=\frac{1}{4}\frac{\Delta [c]}{\Delta t}$

Where $-\frac{\Delta [A]}{\Delta t}$ represents rate of consumption of A and $\frac{\Delta [C]}{\Delta t}$ represents rate of production of C

Here $-\frac{\Delta [A]}{\Delta t}$ = 3 moles/min

So, $\frac{\Delta [C]}{\Delta t}$ = $\frac{4}{2}\times -\frac{\Delta [A]}{\Delta t}$

So, $\frac{\Delta [C]}{\Delta t}$ = $\frac{4}{2}\times (3 moles/min)$

So, $\frac{\Delta [C]}{\Delta t}$ = 6 moles/min