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xz_007 [3.2K]
2 years ago
5

A 6.30 kg piece of solid copper metal at an initial temperature T is placed with 2.00 kg of ice that is initially at -16.0 ∘C. T

he ice is in an insulated container of negligible mass and no heat is exchanged with the surroundings. After thermal equilibrium is reached, there is 0.90 kg of ice and 1.10 kg of liquid water. What was the initial temperature of the piece of copper?
Physics
1 answer:
Viktor [21]2 years ago
3 0

Answer:

179 degree

Explanation:

Solid copper will lose heat to warm up and melt ice . Since all the ice has not melted so final temperature of mixture will be zero.

heat gained by ice to reach temperature of zero degree

= mass of ice x specific heat of ice x rise of temp  

= 2  x 2093 x 16 = 66976 J

Heat gained to melt 1.1. kg of ice

mass x latent heat of ice

1.1 x 334000

= 367400

total heat

= 367400 + 66976

=434376

Heat lost by copper

= 6.3 x 385 x T

where 385 is specific heat of copper and T is initial temperature

heat lost = heat gained

6.3 x 385 T = 434376

T = 434376 / (6.3 x 385)

= 179 degree .

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Power consumption (New) = 55.93kW / .954 = 58.63kW

 

2nd: Total power used in kWh:

Power Used = Power consumption * load factor * Hours:

Power (Old) = 61.46kW * .75 * 4368 = 201343 kWh

Power (New) = 58.63kW * .75 * 4368 = 192072 kWh

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3rd: Calculating for the price:

Price = kW-Hr * $/kWh

Price (Old) = 201343kWh * $0.08/kWh = $16107.44

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4th: Setting up the cost equation:

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Cost (Old) = 5449 + 16107.44*t

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So the payback period is after 35 days.

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