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zimovet [89]
2 years ago
14

Consider the solutions, 0.04 m urea [(NH2)2C=O)], 0.04 m AgNO3 and 0.04 m CaCl2. Which has (i) the highest osmotic pressure, (ii

) the lowest vapor pressure, (iii) the highest boiling point?
Chemistry
1 answer:
Lana71 [14]2 years ago
5 0

Answer:

i) Highest osmotic pressure: CaCl2

ii) lower vapor pressure : CaCl2

iii) highest boiling point : CaCl2

Explanation:

The colligative properties depend upon the number of solute particles in a solution.

The following four are the colligative properties:

a) osmotic pressure : more the concentration of the solute, more the osmotic pressure

b) vapor pressure: more the concentration of the solute, lesser the vapor pressure.

c) elevation in boiling point: more the concentration of the solute, more the boiling point.

d) depression in freezing point: more the concentration of the solute, lesser the freezing point.

the number of particle produced by urea = 1

the number of particle produced by AgNO3 = 2

the number of particle produced by CaCl2 = 3

As concentrations are same, CaCl2 will have more number of solute particles and urea will have least

i) Highest osmotic pressure: CaCl2

ii) lower vapor pressure : CaCl2

iii) highest boiling point : CaCl2

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The compound AX2 decomposes according to the equation, 2 AX2(g) => 2 AX(g) + X2(g). In one experiment, AX2 was measured at va
Karolina [17]

Answer:

0.0011 mol/L.s

Explanation:

The average rate of disappearing of the reagent is the variation of the concentration of it divided by the time that this variation is being measured. The reaction rate, is proportional to the coefficient of the substance, so, for a generic reaction:

aA + bB --> cC + dD

rate = -(1/a)Δ[A]/Δt = -(1/b)Δ[B]/Δt = (1/c)Δ[C]/Δdt = (1/d)Δ[D]/dt

The minus sign is because of the reagent is desapering, so:

rate = -(1/2)*(0.0209 - 0.0300)/(10 - 6)

rate = 0.0011 mol/L.s

8 0
2 years ago
How many moles of koh are contained in 750. ml of 5.00 m koh solution?
Marat540 [252]
Molarity is one of  the method of expressing concentration of solution. Mathematically it is expressed as,
 Molarity = \frac{\text{number of moles of solute}}{\text{volume of solution (l)}}

Given: Molarity of solution = 5.00 M
Volume of solution = 750 ml = 0.750 l

∴ 5 = \frac{\text{number of moles}}{.750}
∴ number of moles = 3.75

Answer: Number of moles of KOH present in solution is 3.75.
4 0
2 years ago
During a lab experiment performed at STP conditions, you prepare HCl by reacting 100. ml of Cl2 gas with an excess of H2 gas.
Brrunno [24]

Answer: 19.4 mL Ba(OH)2

Explanation:

H2(g) + Cl2(g) --> 2HCl(aq) (make sure this equation is balanced first)

At STP, 1 mol gas = 22.4 L gas. Use this conversion factor to convert the 100. mL of Cl2 to moles.

0.100 L Cl2 • (1 mol / 22.4 L) = 0.00446 mol Cl2

Use the mole ratio of 2 mol HCl for every 1 mol Cl2 to find moles of HCl produced.

0.00446 mol Cl2 • (2 mol HCl / 1 mol Cl2) = 0.00892 mol HCl

HCl is a strong acid and Ba(OH)2 is a strong base so both will completely ionize to release H+ and OH- respectively. You need 0.00892 mol OH- to neutralize all of the HCl. Note that one mole of Ba(OH)2 contains 2 moles of OH-.

0.00892 mol OH- • (1 mol Ba(OH)2 / 2 mol OH-) • (1 L Ba(OH)2 / 0.230 M Ba(OH)2) = 0.0194 L = 19.4 mL Ba(OH)2

3 0
2 years ago
What are the coefficients that will balance this skeleton equation? AlCl3 + NaOH → Al(OH)3 + NaCl
almond37 [142]

Answer:

The coefficients are 1, 3, 1, 3

Explanation:

The equation;

AlCl3 + NaOH → Al(OH)3 + NaCl

can be balanced by using the coefficients  1, 3, 1, 3, such that the balanced equation will be;

AlCl3 + 3NaOH → Al(OH)3 + 3NaCl

Chemical equations needs to be balanced so as to follow the law of conservation of mass. This occurs when the number of the different atoms of elements in the reactants side is equal to that of the products side.

3 0
2 years ago
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