A batch of 20 semiconductor chips is inspected by choosing a sample of 3 chips. Assume 10 of the chips do not conform to custome
1 answer:
Answer:
A batch of 20 semiconductor chips is inspected by choosing a sample of 3 chips. Assume 10 of the chips do not conform to customer requirements.
a) Number of different samples = 20C3 = =1140
b) 2 good and one bad chip
Number of samples = 10C2 * 10C1 = 45 * 10 =450
c) 2 good 1 bad + 1 good 2 bad + 3 bad
Number of samples = 10C2 * 10C1 + 10C1 * 10C2 + 10C3
=
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The rate of change of the risk of down syndrome (in percentage of births per year) is
r(x) = 0.004641x² - 0.3012x + 4.9, 20≤ x ≤ 45
where
x = maternal age at delivery.
The function giving risk as a percentage of births when maternal age is x is the integral of r(x). That is,
f(x) = 0.001547x³ - 0.1506x² +4.9x + c
When x = 30, f = 0.14%. Therefore
0.001547(30³) - 0.1506(30²) + 4.9(30) + c = 0.14
41.769 - 135.54 + 147 + c = 0.14
c = -53.089
Answer:
f(x) = 0.001547x³ - 0.1506x² + 4.9x - 53.089, 20 ≤ x ≤ 45
The function is graphed as shown below.
r(x) = 0.004641x² - 0.3012x + 4.9, 20≤ x ≤ 45
where
x = maternal age at delivery.
The function giving risk as a percentage of births when maternal age is x is the integral of r(x). That is,
f(x) = 0.001547x³ - 0.1506x² +4.9x + c
When x = 30, f = 0.14%. Therefore
0.001547(30³) - 0.1506(30²) + 4.9(30) + c = 0.14
41.769 - 135.54 + 147 + c = 0.14
c = -53.089
Answer:
f(x) = 0.001547x³ - 0.1506x² + 4.9x - 53.089, 20 ≤ x ≤ 45
The function is graphed as shown below.
Answer:97 rods
Step-by-step explanation:
The number of steel rods for 95% confidence level
E=3
Substituting values
Thus 97 rods is tested
Answer:
(a) 4.98x10⁻⁵
(b) 7.89x10⁻⁶
(c) 1.89x10⁻⁴
(d) 0.5
(e) 2.9x10⁻²
Step-by-step explanation:
The probability (P) to find the particle is given by:
(1)
The solution of the intregral of equation (1) is:
(a) The probability to find the particle between x = 4.95 nm and 5.05 nm is:
(b) The probability to find the particle between x = 1.95 nm and 2.05 nm is:
(c) The probability to find the particle between x = 9.90 nm and 10.00 nm is:
(d) The probability to find the particle in the right half of the box, that is to say, between x = 0 nm and 50 nm is:
(e) The probability to find the particle in the central third of the box, that is to say, between x = 0 nm and 100/6 nm is:
I hope it helps you!