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Lady bird [3.3K]
2 years ago
8

A realty company looks at a recent sample of houses that have sold On testing the nul hypothesis that 57% of the houses take mor

e than three months to sell against the hypothesis that more than 57% of the houses take more than three months to sell, they find a P value of 0.026 which conclusion is appropriate? Explain.
Choose the correct answer below. A. If 57% of the houses take more than three months to sell, there is a 2 6% chance that a random sample proportion would be as high as or higher than the one they obtained B. There is a 26% chance that 57% of the houses take more than 3 months to sell C. There is a 97 4% chance that 57% of the houses take more than 3 months to sell D. There is a 26% chance that the null hypothesis is correct
Mathematics
1 answer:
Murrr4er [49]2 years ago
7 0

Answer:

The correct option is: If 57% of the houses take more than three months to sell, there is a 2 6% chance that a random sample proportion would be as high as or higher than the one they obtained

Step-by-step explanation:

Consider the provided information.

The Null hypotheses is 57%,

H_0: \mu=0.57\\H_a: \mu>0.57

P-value is given as 0.026

Here P value represents the probability.

0.026 can be written as: 2.6%

Thus the conclusion is:

If 57% of the houses take more than three months to sell, there is a 2 6% chance that a random sample proportion would be as high as or higher than the one they obtained.

Hence, the correct option is: If 57% of the houses take more than three months to sell, there is a 2 6% chance that a random sample proportion would be as high as or higher than the one they obtained

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In 1898 L. J. Bortkiewicz published a book entitled The Law of Small Numbers. He used data collected over 20 years to show that
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Answer:

(a) The probability of more than one death in a corps in a year is 0.1252.

(b) The probability of no deaths in a corps over 7 years is 0.0130.

Step-by-step explanation:

Let <em>X</em> = number of soldiers killed by horse kicks in 1 year.

The random variable X\sim Poisson(\lambda = 0.62).

The probability function of a Poisson distribution is:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...

(a)

Compute the probability of more than one death in a corps in a year as follows:

P (X > 1) = 1 - P (X ≤ 1)

             = 1 - P (X = 0) - P (X = 1)

             =1-\frac{e^{-0.62}(0.62)^{0}}{0!}-\frac{e^{-0.62}(0.62)^{1}}{1!}\\=1-0.54335-0.33144\\=0.12521\\\approx0.1252

Thus, the probability of more than one death in a corps in a year is 0.1252.

(b)

The average deaths over 7 year period is: \lambda=7\times0.62=4.34

Compute the probability of no deaths in a corps over 7 years as follows:

P(X=0)=\frac{e^{-4.34}(4.34)^{0}}{0!}=0.01304\approx0.0130

Thus, the probability of no deaths in a corps over 7 years is 0.0130.

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2 years ago
matthew is planning dinners for the next 3 nights. there’s are 11 meals to choose from. If no meal is repeated, how many differe
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I hope this helps.

Step-by-step explanation:

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