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QveST [7]
2 years ago
9

As the performance of PCs steadily improves, computers that in the past were classified as midrange computers are now marketed a

s ____.
laptops
PC servers
PDAs
tablet PCs
Computers and Technology
1 answer:
taurus [48]2 years ago
5 0

Answer: PC servers

Explanation: PC(Personal computer) servers are the helps in the utilization of the network services to the software and hardware of the computer. It manages the network resources . In the past time ,Mindrange computers, mini computers etc are present time's PC servers.

Other options are incorrect because laptops ,PDA(Personal digital assistant) or tablets are the modern version of the computer units that are portable and compact with fast processing. Thus the correct option is option PC servers.

You might be interested in
7. Test Average and Grade Write a program that asks the user to enter five test scores. The program should display a letter grad
Alenkasestr [34]

Answer:

The code solution is written in Java.

  1. import java.util.Scanner;
  2. public class TestScore {
  3.    public static void main(String[] args) {
  4.        Scanner input = new Scanner(System.in);
  5.        System.out.print("Please enter first score: ");
  6.        double firstScore = input.nextDouble();
  7.        System.out.println("Grade: " + determineGrade(firstScore));
  8.        System.out.print("Please enter second score: ");
  9.        double secondScore = input.nextDouble();
  10.        System.out.println("Grade: " + determineGrade(secondScore));
  11.        System.out.print("Please enter third score: ");
  12.        double thirdScore = input.nextDouble();
  13.        System.out.println("Grade: " + determineGrade(thirdScore));
  14.        System.out.print("Please enter fourth score: ");
  15.        double fourthScore = input.nextDouble();
  16.        System.out.println("Grade: " + determineGrade(fourthScore));
  17.        System.out.print("Please enter fifth score: ");
  18.        double fifthScore = input.nextDouble();
  19.        System.out.println("Grade: " + determineGrade(fifthScore));
  20.        System.out.println("Average score: " + calcAverage(firstScore, secondScore, thirdScore, fourthScore, fifthScore));
  21.    }
  22.    public static double calcAverage(double score1, double score2, double score3, double score4, double score5){
  23.        double average = (score1 + score2 + score3 + score4 + score5) / 5;
  24.        return average;
  25.    }
  26.    public static String determineGrade(double score){
  27.        if(score >= 90){
  28.            return "A";
  29.        }
  30.        else if(score >= 80 ){
  31.            return "B";
  32.        }
  33.        else if(score >=70){
  34.            return "C";
  35.        }
  36.        else if(score >=60){
  37.            return "D";
  38.        }
  39.        else{
  40.            return "F";
  41.        }
  42.    }
  43. }

Explanation:

Firstly, create the method, <em>calcAverage()</em>, that takes five test scores. Within the method, calculate the average and return it as output. (Line 33 - 36)

Next, create another method, <em>determineGrade()</em>, which takes only one score and return the grade based on the range of the  score. (Line 38 -54)

Once the two required methods are created, we are ready to prompt use for input five test scores using Java Scanner class. To use get user input, create a Scanner object (Line 7). Next, use getDouble() method to get an input score and assign it to variables firstScore, secondScore, thirdScore, fourthScore & fifthScore, respectively. Once a score input by user, call determineGrade() method by passing the input score as argument and immediately print out the return grade. (Line  9 - 27)

At last, call calcAverage() method by passing the first test score variables as argument and print out the returned average value. (Line 29).

5 0
2 years ago
For multicore processors to be used effectively, computers must understand how to divide tasks into parts that can be distribute
AnnyKZ [126]

Answer: parallel processing

Explanation:

Parallel processing is the process by which the processor has the capacity to execute parallel instruction at the same time. This is possible only by assigning the different task to the different cores present in the cpu. So a cpu with multiple cores are able to process multiple task as the same time parallel.

8 0
2 years ago
If you were investigating login issues on a Windows computer, which portion of the Event Viewer logs would be a good place to st
USPshnik [31]

Answer:

If we are investigating login issues then we have to start with 'security logs' in 'windows logs' portion of Event viewer.

Explanation:

Much information about login issues is contained in log files which are related to security because it is mostly security issue. Some it is also better to start with 'system logs' portion of windows logs portion of Event viewer when there may be system problems instead of security issues. But in most cases there is security issues so 'security logs' is better option overall

6 0
2 years ago
Describe the output when the following code executes in 64-bit mode: .data dividend_hi QWORD 00000108h dividend_lo QWORD 3330002
iragen [17]

Answer:

RAX = 333000h (16 bits with preceding zeros removed)

RDX = 20h (also 16 bits with preceding zeros removed)

Explanation:

The "div" opcode in the assembly language source code is used to divide operands. It accepts a divisor ( the denominator) and divides the content of the AX register. The result is saved in the AX register while the remainder (if any) is saved in the DX register. If the DX register holds any data, the data is replaced with the divisor remnant.

The code above divides the content of the RAX register with the divisor variable and saves the result and remainder in the RAX and RDX respectively.

7 0
2 years ago
This question involves the creation of user names for an online system. A user name is created based on a user’s first and last
Evgen [1.6K]

Answer:

See explaination

Explanation:

import java.util.*;

class UserName{

ArrayList<String> possibleNames;

UserName(String firstName, String lastName){

if(this.isValidName(firstName) && this.isValidName(lastName)){

possibleNames = new ArrayList<String>();

for(int i=1;i<firstName.length()+1;i++){

possibleNames.add(lastName+firstName.substring(0,i));

}

}else{

System.out.println("firstName and lastName must contain letters only.");

}

}

public boolean isUsed(String name, String[] arr){

for(int i=0;i<arr.length;i++){

if(name.equals(arr[i]))

return true;

}

return false;

}

public void setAvailableUserNames(String[] usedNames){

String[] names = new String[this.possibleNames.size()];

names = this.possibleNames.toArray(names);

for(int i=0;i<usedNames.length;i++){

if(isUsed(usedNames[i],names)){

int index = this.possibleNames.indexOf(usedNames[i]);

this.possibleNames.remove(index);

names = new String[this.possibleNames.size()];

names = this.possibleNames.toArray(names);

}

}

}

public boolean isValidName(String str){

if(str.length()==0) return false;

for(int i=0;i<str.length();i++){

if(str.charAt(i)<'a'||str.charAt(i)>'z' && (str.charAt(i)<'A' || str.charAt(i)>'Z'))

return false;

}

return true;

}

public static void main(String[] args) {

UserName person1 = new UserName("john","smith");

System.out.println(person1.possibleNames);

String[] used = {"harta","hartm","harty"};

UserName person2 = new UserName("mary","hart");

System.out.println("possibleNames before removing: "+person2.possibleNames);

person2.setAvailableUserNames(used);

System.out.println("possibleNames after removing: "+person2.possibleNames);

}

}

8 0
2 years ago
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