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ikadub [295]
2 years ago
4

Compare the distance between the molecules of a gas in a very small container with the distance

Chemistry
1 answer:
krok68 [10]2 years ago
3 0

Answer:

The distance between the gas molecules in the small container in smaller as compare to the distance between the gas molecule in large container.

Explanation:

we know that gas consist of large number of tiny molecules. Gas molecules  randomly move in the container. If the same amount of gas is placed into a small container and the large container, the distance between the gas molecules is larger in large container. The reason is that in case of large container gas molecules found more space to move randomly and move distance apart from each other. while in small container they are relatively close to each other because of smaller available space.

It can be understand through the example of 50 students in small room and in a large room. The students are more close to each other in smaller room because of small given space while in case of large room 50 students can be placed at more distance from each others because of large volume.

Properties of gas molecules:

Gas molecules  randomly move in the container.

The volume of gas molecules as compare to the volume of container is negligible.

The gas molecules collide with each other and also with the walls of container but this collision is elastic.

There is no attraction or repulsion between gas molecules.

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A sample of a solid labeled as NaCl may be impure. a student analyzes the sample and determines that it contains 75 percent chlo
Evgesh-ka [11]

Answer:

D

Explanation:

The sample must contain impurity that is lower in atomic mass to sodium and since potassium has higher atomic mass to sodium, the answer is the sample contains NaCl and LiCl. We are sure already that the sample is not pure which rules out  option a and option b contains sodium iodide which cannot contribute to the increase in chlorine

5 0
2 years ago
Which equation shows the proper setup to find the volume of a 0.250 M CaCl2 solution that contains 39.5 g of CaCl2?
Jlenok [28]
Molarity = number of mole of substance(n) / volume of solution (V).

n(CaCl2) = mass (CaCl2)/M(CaCl2)

M(CaCl2) = 40+2*35.5 = 111 g/mol 

n(CaCl2) =39.5 g CaCl2*1 mol/111g

0.250 M = 39.5 g CaCl2*1 mol/111g*volume of solution (V).

volume of solution (V) = 39.5 g CaCl2*1 mol/(0.250 M*111g) = 1.42 L
4 0
2 years ago
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Why are the concentrations of [H3O+] and [OH−] equal in pure water?
kotegsom [21]

Answer : The correct option is, (A) [H_3O^+]=[OH^-] because one of each is produced every time an [H^+] transfers from one water molecule to another.

Explanation :

As we know that, when the two water molecule combine to produced hydronium ion and hydroxide ion.

The balanced reaction will be:

HOH+HOH\rightarrow H_3O^++OH^-

Acid : It is a substance that donates hydrogen ion when dissolved in water.

Base : It is a substance that accepts hydrogen ion when dissolved in water.

From this we conclude that, the hydrogen ion are transferred from one water molecule to the another water molecule to form hydronium ion and hydroxide ion. In this reaction, one water molecule will act as a base and another water molecule will act as an acid.

Hence, the correct option is, (A)

3 0
2 years ago
Keiko needs 100mL of a 5% acid solution for a science experiment. She has available a 1% solution and a 6% solution. How many mi
4vir4ik [10]

Answer:

Keiko should mix 20 mL 1% solution and 80 mL 6% solution for to make 100 mL 5% solution

Explanation:

There are 2 unknown values X= mL 6% solution and Y=1% solution. So, we need 2 equations:

1. Equation acid concentration. X mL 6% + Y mL 1% = 100 mL 5%

2. Equation solvent concentration X mL 94% + Y mL 99% = 100 mL 95%

When clearing X and Y :

(X mL 6%    +   Y mL 1%      =    100 mL 5%) (-15,7)

X mL 94%  +   Y mL 99%   =   100 mL 95%

_______________________________

 -                      Y  0.83       =   16.5

                        Y                =   19.9 mL 1% solution

Replace Y in anyone equation and X = 80 mL 6% solution

I hope to see been helpful

7 0
2 years ago
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