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Pachacha [2.7K]
2 years ago
3

an open square-based container is made by cutting 4 cm square pieces out of a piece of tinplate if the volume of the container i

s 120cm^3 find the size of the original piece of tinplate
Mathematics
1 answer:
mars1129 [50]2 years ago
3 0
Original measures of the tinplate square: x cm * x cm

Measure of thesides of the tinplate after cutting two 4 cm square pieces out of each side: [x - 8]*[x - 8] (this is the base of the container)

Volume of the container =: area of the base * height

area of the base = [x - 8]^2

height = 4 cm

Volume of the container 4*[x - 8]^2 = 120 cm^3

Divide both sides by 4: [x - 8]^2 = 30 cm^2

Extract square root from both sides: [x - 8] = √(30 cm^2)

 [x - 8] ≈ 5.5 cm

x ≈ 5.5cm + 8 cm ≈ 13.5 cm

Answer: the side of the original tinplate square was approximately 13.3 cm 

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<span>A circle is centered at the point (-3, 2) and passes through the point (1, 5). The radius of the circle is 5_ units. The points(-7,5) and (-7,-1</span>) lie on this circle.
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2 years ago
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in germany, VAT is at 19% Jeremy buys a calculator in germny for €58.31 This price includes VAT Find the amount of VAT paid by
Len [333]

We can use this equation to solve this problem:

<span>t=p+<span>(p⋅r)</span></span>

Where:

t is the total price paid: 58.31 for this problem

p is the price before taxes: What we are solving for in this problem.

r is the tax or VAT rate: 19% for this problem. "Percent" or "%" means "out of 100" or "per 100", Therefore 19% can be written as <span>19100</span> or 0.19.

Substituting and solving for p gives:

<span>58.31=p+<span>(p⋅0.19)</span></span>

<span>58.31=1p+0.19p</span>

<span>58.31=<span>(1+0.19)</span>p</span>

<span>58.31=1.19p</span>

<span><span>58.311.19</span>=<span><span>1.19p</span>1.19</span></span>

<span>49=<span><span>1.19p</span>1.19</span></span>

<span>49=p</span>

<span>p=49</span>

Now, we can find how much the VAT was by taking 19% of 49:

<span>19%×49=0.19×49=9.31</span>

Another was to solve this is to subtract the price without the tax or VAT from the total price giving:

<span>58.31−49=<span>9.31</span></span>

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Noor wants to spend less than $20 on condiments. Each kilogram of salt costs $1.50, and each kilogram of pepper costs 2.50.
nata0808 [166]

Answer:

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Step-by-step explanation:

Multiply by each kilo and then make sure it adds up to less than 20!

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Problem 2.2.4 Your Starburst candy has 12 pieces, three pieces of each of four flavors: berry, lemon, orange, and cherry, arrang
kkurt [141]

Answer:

a) P=0

b) P=0.164

c) P=0.145

Step-by-step explanation:

We have 12 pieces, with 3 of each of the 4 flavors.

You draw the first 4 pieces.

a) The probability of getting all of the same flavor is 0, because there are only 3 pieces of each flavor. Once you get the 3 of the same flavor, there are only the other flavors remaining.

b) The probability of all 4 being from different flavor can be calculated as the multiplication of 4 probabilities.

The first probability is for the first draw, and has a value of 1, as any flavor will be ok.

The second probability corresponds to drawing the second candy and getting a different flavor. There are 2 pieces of the flavor from draw 1, and 9 from the other flavors, so this probability is 9/(9+2)=9/11≈0.82.

The third probability is getting in the third draw a different flavor from the previos two draws. We have left 10 candys and 4 are from the flavor we already picked. Then the third probabilty is 6/10=0.6.

The fourth probability is getting the last flavor. There are 9 candies left and only 3 are of the flavor that hasn't been picked yet. Then, the probability is 3/9=0.33.

Then, the probabilty of picking the 4 from different flavors is:

P=1\cdot\dfrac{9}{11}\cdot\dfrac{6}{10}\cdot\dfrac{3}{9}=\dfrac{162}{990}\approx0.164

c) We can repeat the method for the previous probabilty.

The first draw has a probability of 1 because any flavor is ok.

In the second draw, we may get the same flavor, with probability 2/11, or we can get a second flavor with probability 9/11. These two branches are ok.

For the third draw, if we have gotten 2 of the same flavor (P=2/11), we have to get a different flavor (we can not have 3 of the same flavor). This happen with probability 9/10.

If we have gotten two diffente flavors, there are left 4 candies of the picked flavors in the remaining 10 candies, so we have a probabilty of 4/10.

For the fourth draw, independently of the three draws, there are only 2 candies left that satisfy the condition, so we have a probability of 2/9.

For the first path, where we pick 2 candies of the same flavor first and 2 candies of the same flavor last, we have two versions, one for each flavor, so we multiply this probability by a factor of 2.

We have then the probabilty as:

P=2\cdot\left(1\cdot\dfrac{2}{11}\right)\cdot\left(\dfrac{9}{10}\cdot\dfrac{2}{9}\right)+\left(1\cdot\dfrac{9}{11}\cdot\dfrac{4}{10}\cdot\dfrac{2}{9}\right)\\\\\\P=2\cdot\dfrac{36}{990}+\dfrac{72}{990}=\dfrac{144}{990}\approx0.145

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2 years ago
Ron and amie opened an educational savings account for their daughter when she was born making a $5,000 initial investment. They
Arlecino [84]

Interest rate= 0.083%

Step-by-step explanation:

Principal= $5000 Amount= $10000 Time period= 12 years

A=Amount, P= Principal, I= Simple Interest r= Rate of interest t= Time period

A= P+ I\\10000= 5000+ I\\I=10000-5000=5000\\I=Prt\\5000=5000*r*12\\r=5000/5000*12\\r=5000/60000\\r=0.083

6 0
2 years ago
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