Question

A tall tube is evacuated, and its stopcock closed. The open end of the tube is immersed into a container of water (density 103 kg/m3) that is open to the atmosphere (pressure 105 N/m2). When the stopcock is opened, how far up the tube will the water rise? A.1 m B.5 m C.10 m D.20 m

Answer 1

Explanation:

It is given that,

Density of water, $d=10^3\ kg/m^3$

Atmospheric pressure, $P=10^5\ N/m^2$

The pressure exerted at a height h is given by :

$P=d\times g\times h$

g is acceleration due to gravity

$h=\dfrac{P}{dg}$

$h=\dfrac{10^5}{10^3\times 9.8}$

h = 10.2 meters

or

h = 10 meters

So, the water will rise to a height of 10 meters. Hence, this is the required solution.