Answer:
Length of sides of poster = 2 Ft
Length of sides of box = 2.41 Ft
Since the box has a longer side than the poster, the poster will lie flat when placed in the box.
Step-by-step explanation:
In order to determine if the poster will lie flat in the box or not, we will determine the length of the sides of the poster and the box, if the length of the side of the square poster is smaller than that of the box, it will lie flat. This is calculated as follows:
Area of poster = 4 square feet
Area of poster = (Length)²
4 = (Length)²
∴ Length = √(4)
Length of poster = 2 Ft
Volume of box = 14 cubic feet
Volume of box = (Length)³
14 = (Length)³
∴ Length = ∛(14)
Length = 2.41 Ft
∴ Length of sides of poster = 2 Ft
Length of sides of box = 2.41 Ft
Since the box has a longer side than the poster, the poster will lie flat when placed in the box.
Answer:
There is an 85.5% probability that both stages meet specifications.
Step-by-step explanation:
We have these following probabilities:
A 90% probability that the first stage meets specifications.
If the first stage meets specifications, a 95% probability that the second stage also meets specifications.
What is the probability that both stages meet specifications?
This is the multiplication of these probabilities. So:
There is an 85.5% probability that both stages meet specifications.
Answer:
The probability that a particular driver had exactly two speeding violations is 0.009.
Step-by-step explanation:
We are given that a sample of 2,000 licensed drivers revealed the following number of speeding violations;
<u>Number of Violations</u> <u>Number of Drivers</u>
0 1,910
1 46
2 18
3 12
4 9
5 or more <u> 5 </u>
<u>Total</u> <u> 2000 </u>
<u />
Now, the data means that 1,910 drivers had 0 speeding violations and so on.
Now, we have to find the probability that a particular driver had exactly two speeding violations, that means;
Number of drivers having exactly two speeding violations = 18
Total numbers of drivers = 2000
So, the required probability = 
= 
= <u>0.009</u>
Given: 1 cm = 2 3/4 ft ; kitchen length = 4 1/2 cm
2 3/4 = 11/4; 4 1/2= 9/2
11/4 x 9/2 = 99/8 =12 3/8
OR You could use decimals
2 3/4 = 2.75 ; 4 1/2 = 4.5
2.75 x 4.5 = 12.375
12.375 = 12 375/1000 or 12 3/8
Okay, well we start out with the equation P=66, where P is perimeter. You should create equations using variables to explain each piece of information you are given. Follow the equations below and see if you can understand how to do another one like this. In this problem, l is length and w is width.
P = 66 The perimeter is equal to 66
l = 3 + w The length of one side is 3 more than the width
2l + 2w = 66 A rectangle's perimeter is calculated by adding the lengths and widths
2(3 + w) + 2w = 66 Use what you know about length from step 2 to replace the variable in step 3
6 + 2w + 2w = 66 Multiply
6 + 4w = 66 Add like terms
4w = 60 Subtract
w = 15 Divide
l = 3 + w Remember step 2?
l = 3 + 15 Replace the variable using your value for w
l = 18 Add
And you're done! Always check your work. It helps to create a picture of a rectangle while you're doing these problems as well. As you get used to these problems more and more, you can show more or less work than I've shown, but try to stay true to what the teacher asks of you. Good luck!
