If a force of 65 N is exerted on a 45 kg sofa and the sofa is moved 6.0 meters, how much work is done in moving the sofa? 17,550
2 answers:
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Answer:
Distance between peak height (vertically) of projectile and mountain height = (2975.2 - 1800) = 1175.2 m
Distance between where the projectile lands and ship B = (3188.8 - 3110) = 8.8 m
Explanation:
Given the velocity and angle of shot of the projectile, one can calculate the range and maximum height attained by the projectile.
H = (v₀² Sin²θ)/2g
v₀ = initial velocity of projectile = 2.50 × 10² m/s = 250 m/s
θ = 75°, g = 9.8 m/s²
H = 250² (Sin² 75)/(2 × 9.8) = 2975.2 m
Range of projectile
R = v₀² (sin2θ)/g
R = 250² (sin2×75)/9.8
R = 250² (sin 150)/9.8 = 3188.8 m
Height of mountain = 1.80 × 10³ = 1800 m
Maximum height of projectile = 2975.2 m
Distance between peak height (vertically) of projectile and mountain height = 2975.2 - 1800 = 1175.2 m
Distance of ship B from ship A = 2.5 × 10³ + 6.1 × 10² = 2500 + 610 = 3110 m
Range of projectile = 3188.8 m
Distance between where the projectile lands and ship B = 3188.8 - 3110 = 8.8 m
a) The speed of the student after the jump is 1.07 m/s
b) The final speed of the laser is 10.4 m/s
Explanation:
a)
We can solve this problem by applying the law of conservation of momentum: if there are no external forces acting on the system, the total momentum of the student+Laser system must be constant. Therefore, we can write:
where
The initial momentum is zero
m = 42 kg is the mass of the Laser
v = 1.5 m/s is the final velocity of the Laser
M = 59 kg is the mass of the student
V is the final velocity of the student
Solving the equation for V, we find the velocity of the student:
So, the final speed of the student is 1.07 m/s.
b)
In this case, the laser and the student are travelling at 3.1 m/s before the student jumps off: therefore, the total momentum before the jump is not zero.
So, the equation of the conservation of momentum is
where
m = 42 kg is the mass of the Laser
M = 59 kg is the student's mass
u = 3.1 m/s is the initial velocity of the student and the Laser
V = -2.1 m/s is the velocity of the student after the jump (she jumps backward)
v is the final velocity of the Laser
And solving for v, we find
Learn more about momentum:
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