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2 years ago

What is the molar mass of magnesium sulfate heptahydrate (MgSO4⋅ 7H2O) ?

Chemistry

2 answers:

KatRina [158]2 years ago

7 0

Answer:

option D = 246 g/mol

Explanation:

Molar mass of MgSO₄⋅ 7H₂O:

Molar mass = 24.305 + 32.065 + 16×4 + 7 (1.008×2 +16)

Molar mass = 24.305 + 32.065 + 64 + 7 (18.016)

Molar mass = 24.305 + 32.065 + 64 + 126.112

Molar mass = 246.482 g /mol

lana66690 [7]2 years ago

3 0

Answer : The correct option is, 246 g/mol

Explanation :

Molar mass : It is defined as the mass in grams of one mole of substance and each element has its own unique molar mass. It is expressed in grams/mole or g/mol. It is equal to the mass of atom present in 1 mole.

Molar mass of Mg = 24 g/mole

Molar mass of S = 32 g/mole

Molar mass of O = 16 g/mole

Molar mass of H = 1 g/mole

Now we have to determine the molar mass of $MgSO_4.7H_2O$

$\text{Molar mass of }MgSO_4.7H_2O=\text{Molar mass of }Mg+\text{Molar mass of }S+11\times \text{Molar mass of }O+14\times \text{Molar mass of }H$

$\text{Molar mass of }MgSO_4.7H_2O=[24+32+11(16)+14(1)]=246g/mol$

Therefore, the molar mass of $MgSO_4.7H_2O$ is 246 g/mol

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Answer:

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S°, NO2(g) = 240.06 J/mol.K

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ΔS° = -268.13 J/K

b. N2(g) + 3F2(g) → 2NF3(g)

S°, N2(g) = 191.61 J/mol.K

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S°, NF3(g) = 260.0 J/mol.K

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ΔS° = -279.95 J/K

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